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Vladimir79 [104]
3 years ago
14

The asymptote of the functio f (x) =3^x +4 is y

Mathematics
2 answers:
Y_Kistochka [10]3 years ago
5 0
Since that f is continuous for all x in R, and f > 0 then

                            \lim\limits_{x\to -\infty}3^x+4=4

for hence the asymptote is y = 4


NISA [10]3 years ago
5 0
There aren't any asymptotes of the graph.
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Answer:

It depends on the person, I personally work better plugging in numbers and practicing with numbers I like. I say just try different ways and see what works best for you.

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3 years ago
Learning outcome: Solve a linear system of equations in two and three variables using algebraic methods. Read and solve word pro
Talja [164]

Answer: Equilibrium price would be $13.33 and equilibrium quantity  would be 133.3 units.

Step-by-step explanation:

Since we have given that

Demand function is stated as

D(p)=200-5p

Supply function is stated as

S(p)=10p

We need to find the equilibrium price and quantity for this device.

For equilibrium, D(p) = S(p).

so, it becomes,

200-5p=10p\\\\200=10p+5p\\\\200=15p\\\\p=\dfrac{200}{15}\\\\p=\$13.33

and when we put the value of p in any function:

Q=10\times 13.33=133.3\ units

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8 0
3 years ago
Write the equation of the blue line using slope intercept form (y=mx+b)
dalvyx [7]

Answer:

Step-by-step explanation:

X1=-4

Y1=7

X2=-3

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5 0
2 years ago
Factor the expression completely
Anastaziya [24]
25c - 5

Simplify all of the answer choices & see which one is correct.

a) 5(5c - 1)

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A) IS CORRECT.

b) 5(20c + 1)

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B IS INCORRECT.

c) 5(5c)

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C IS INCORRECT.

d) 5(c -1 )

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D IS INCORRECT.

Therefore, the correct answer is a) 5(5c - 1)

~Hope I helped!~
7 0
3 years ago
Read 2 more answers
Jamie is riding a Ferris wheel that takes fifteen seconds for each complete revolution. The diameter of the wheel is 10 meters a
Agata [3.3K]

Answer:

The answers to the question is

(a) Jamie is gaining altitude at 1.676 m/s

(b) Jamie rising most rapidly at t = 15 s

At a rate of 2.094 m/s.

Step-by-step explanation:

(a) The time to make one complete revolution = period T = 15 seconds

Here will be required to develop the periodic motion equation thus

One complete revolution = 2π,

therefore the  we have T = 2π/k = 15

Therefore k = 2π/15

The diameter = radius of the wheel = (diameter of wheel)/2 = 5

also we note that the center of the wheel is 6 m above ground

We write our equation in the form

y = 5*sin(\frac{2*\pi*t}{15} )+6

When Jamie is 9 meters above the ground and rising we have

9 = 5*sin(\frac{2*\pi*t}{15} )+6 or 3/5 = sin(\frac{2*\pi*t}{15} ) = 0.6

which gives sin⁻¹(0.6) = 0.643 =\frac{2*\pi*t}{15}

from where t = 1.536 s

Therefore Jamie is gaining altitude at

\frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi t}{15}) = 1.676 m/s.

(b) Jamie is rising most rapidly when   the velocity curve is at the highest point, that is where the slope is zero

Therefore we differentiate the equation for the velocity again to get

\frac{d^2y}{dx^2} = -5*(\frac{\pi *2}{15} )^2*sin(\frac{2\pi t}{15}) =0, π, 2π

Therefore -sin(\frac{2\pi t}{15} ) = 0 whereby t = 0 or

\frac{2\pi t}{15} = π and t =  7.5 s, at 2·π t = 15 s

Plugging the value of t into the velocity equation we have

\frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi t}{15}) = - 2/3π m/s which is decreasing

so we try at t = 15 s and we have \frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi *15}{15}) = \frac{2}{3} \pim/s

Hence Jamie is rising most rapidly at t = 15 s

The maximum rate of Jamie's rise is 2/3π m/s or 2.094 m/s.

7 0
3 years ago
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