Answer:
a = -1
b = -9
c = 9
d = 3
e = 3
f = 2
g = 3/2
Step-by-step explanation:
* Lets explain how to solve the problem
∵ 
are rational fractions
- To add or subtract the rational fractions they must have same
denominator
∵ 6 - 2x must be written 2x - 6, take (-1) as a common factor from 6 - 2x
∴ - 1(-6 + 2x) = - 1(2x - 6)
∴ 
∴ a = -1
∵ 9 ÷ -1 = -9
∴ = 
∴ b = -9
∵ The denominators of the two fractions are 2x - 6
∴ We can add them by adding their numerator
∵ 3x + -9 = 3x - 9
∴ = 
∴ c = 9
∵ 3x - 9 has a common factor 3
∴ 3x - 9 = 3(x - 3)
∵ 2x - 6 has common factor 2
∴ 2x - 6 = 2(x - 3)
∴ = 
∴ d = 3 , e = 3 , f = 2
- The fraction has same factor (x - 3) up and down then we can cancel
them together
∴ = 
∴ g = 3/2
Answer: 
Step-by-step explanation:
Given: The first term of Geometric series : a=1
The seconds term of Geometric series : 
The common ratio between the terms is given by :-
We know that the sum of infinite geometric series is given by :-
Hence, the sum of the given infinite series =
Answer:
10 friends
Step-by-step explanation:
we know that
The formula of the sum is equal to
![sum=\frac{n}{2}[2a1+(n-1)d]](https://tex.z-dn.net/?f=sum%3D%5Cfrac%7Bn%7D%7B2%7D%5B2a1%2B%28n-1%29d%5D)
where
a1 is the first term
n is the number of terms (number of friends)
d is the common difference in the arithmetic sequence
In this problem we have
----> the common difference
substitute in the formula and solve for n
![275=\frac{n}{2}[2(5)+(n-1)(5)]](https://tex.z-dn.net/?f=275%3D%5Cfrac%7Bn%7D%7B2%7D%5B2%285%29%2B%28n-1%29%285%29%5D)
![550=n[10+5n-5]\\ \\550=10n+5n^{2} -5n\\ \\5n^{2}+5n-550=0](https://tex.z-dn.net/?f=550%3Dn%5B10%2B5n-5%5D%5C%5C%20%5C%5C550%3D10n%2B5n%5E%7B2%7D%20-5n%5C%5C%20%5C%5C5n%5E%7B2%7D%2B5n-550%3D0)
Solve the quadratic equation by graphing
The solution is n=10
see the attached figure
therefore
She had 10 friends who got stickers
3.60 / 60cm = .06/cm or 6 cents per centimeter
100cm = 1m
$.06 * 100cm = $6.00 / m
100m = 100 * $6.00
= $600
Answer:
Equation: 6+d-18
d = difference of a number and eighteen
Idk if it helps. :|
