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Alisiya [41]
4 years ago
11

JN is ? between angle J and angle K

Mathematics
1 answer:
crimeas [40]4 years ago
7 0
Verify please dont understand
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Select the correct answer.
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Step-by-step explanation:

7 0
3 years ago
Raise the quality in parentheses to the indicated exponent, and simplify the resulting expression with positive exponents.
finlep [7]

For this case we have the following expression:

(\frac {-27x ^ 0 * y ^ {- 2}} {54x ^ {- 5} * y ^ {- 4}}) ^ {- 2} =

By definition we have to:

a^0 = 1

So:

(\frac {-27y ^ {- 2}} {54x ^ {- 5} * y ^ {- 4}}) ^ {- 2} =

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(\frac {-y ^ {- 2}} {2x ^ {- 5} * y ^ {- 4}}) ^ {- 2} =

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So, rewriting the expression we have:

(-1)^{-2}\frac{-y^{-2*-2}}{2^{-2}*x^{-5*-2}*y^{-4*-2}}=\\\frac{1}{(-1)^2}*\frac{-y^{4}}{2^{-2}x^{10}*y^{8}}=

SImplifying:

+1*\frac{y^{4-8}}{2^{-2}x^{10}}=\\\frac{y^{-4}}{2^{-2}x^{10}}=\\\frac{2^2}{x^{10}y^{4}}

Answer:

\frac{4}{x^{10}y^{4}}

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