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lana66690 [7]
4 years ago
6

Raise the quality in parentheses to the indicated exponent, and simplify the resulting expression with positive exponents.

Mathematics
1 answer:
finlep [7]4 years ago
8 0

For this case we have the following expression:

(\frac {-27x ^ 0 * y ^ {- 2}} {54x ^ {- 5} * y ^ {- 4}}) ^ {- 2} =

By definition we have to:

a^0 = 1

So:

(\frac {-27y ^ {- 2}} {54x ^ {- 5} * y ^ {- 4}}) ^ {- 2} =

Simplifying:

(\frac {-y ^ {- 2}} {2x ^ {- 5} * y ^ {- 4}}) ^ {- 2} =

By definition of power properties we have to:

(a ^ n) ^ m = a ^ {n * m}

So, rewriting the expression we have:

(-1)^{-2}\frac{-y^{-2*-2}}{2^{-2}*x^{-5*-2}*y^{-4*-2}}=\\\frac{1}{(-1)^2}*\frac{-y^{4}}{2^{-2}x^{10}*y^{8}}=

SImplifying:

+1*\frac{y^{4-8}}{2^{-2}x^{10}}=\\\frac{y^{-4}}{2^{-2}x^{10}}=\\\frac{2^2}{x^{10}y^{4}}

Answer:

\frac{4}{x^{10}y^{4}}

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s2008m [1.1K]

Answer:

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3 years ago
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Can someone please give me the answer to this
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Hello!

\large\boxed{y = 2x - 4}

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3 years ago
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denpristay [2]

Answer:

  y = -3x -4

Step-by-step explanation:

A perpendicular line has a slope that is the negative reciprocal of that of the given line. When the equation starts out in standard form, a line with negative reciprocal slope can be written by swapping the x- and y-coefficients and negating one of them.

The given x- and y-coefficients have the ratio 1:-3, so we can use the coefficients 3 and 1 for our purpose.

The usual process of making the line go through a given point can be used. That is, we can translate the line from the origin to the desired point by subtracting the point coordinates from x and y. Then we have ...

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This is "an" equation. It is in no particularly recognizable form. It can be rearranged to the form y = mx + b:

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8 0
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How do I solve?<br><br> -2x2y3 · 14x2y3
Sever21 [200]
(-2x2y3)(14x2y3) = -28x^4y^6
7 0
3 years ago
Equivalent fractions for 3/5
Tcecarenko [31]
9/15

6/10

12/20

15/25

18/30

Hope this helps!! :)
7 0
3 years ago
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