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lana66690 [7]
3 years ago
6

Raise the quality in parentheses to the indicated exponent, and simplify the resulting expression with positive exponents.

Mathematics
1 answer:
finlep [7]3 years ago
8 0

For this case we have the following expression:

(\frac {-27x ^ 0 * y ^ {- 2}} {54x ^ {- 5} * y ^ {- 4}}) ^ {- 2} =

By definition we have to:

a^0 = 1

So:

(\frac {-27y ^ {- 2}} {54x ^ {- 5} * y ^ {- 4}}) ^ {- 2} =

Simplifying:

(\frac {-y ^ {- 2}} {2x ^ {- 5} * y ^ {- 4}}) ^ {- 2} =

By definition of power properties we have to:

(a ^ n) ^ m = a ^ {n * m}

So, rewriting the expression we have:

(-1)^{-2}\frac{-y^{-2*-2}}{2^{-2}*x^{-5*-2}*y^{-4*-2}}=\\\frac{1}{(-1)^2}*\frac{-y^{4}}{2^{-2}x^{10}*y^{8}}=

SImplifying:

+1*\frac{y^{4-8}}{2^{-2}x^{10}}=\\\frac{y^{-4}}{2^{-2}x^{10}}=\\\frac{2^2}{x^{10}y^{4}}

Answer:

\frac{4}{x^{10}y^{4}}

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Suppose you are making granola bars with 3 cups of oats. How much quinoa, flaxseed, and soy protein would you use would you need
Andreas93 [3]

Answer: \frac{3}{4}\ cup of quinoa, \frac{3}{8}\ cup of flaxseed, 1\ cup of soy protein.

Step-by-step explanation:

<h3> The missing table is attached.</h3>

Let be "q" the amount of cups of quinoa you'd need to use making the granolas with 3 cups of oats.

Based on the table you can write the following proportion:

\frac{\frac{1}{2} }{2}=\frac{q}{3}

Solving for "q", you get:

\frac{1}{4}=\frac{q}{3}\\\\q=\frac{3}{4}

 Let be "f" the amount of cups of flaxseed you'd need to use making the granolas with 3 cups of oats.

With the data given in the table you can write the following proportion:

\frac{\frac{1}{4} }{2}=\frac{f}{3}

Solving for "f", you get:

\frac{1}{8}=\frac{f}{3}\\\\f=\frac{3}{8}

Let be "s" the amount of cups of soy protein you'd need to use making the granolas with 3 cups of oats.

Using the table you can write this proportion:

\frac{\frac{2}{3} }{2}=\frac{s}{3}

Solving for "s", you get:

\frac{1}{3}=\frac{s}{3}\\\\s=1

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