1. Let's call:
x: the width of the walkway.
b: 2x+16 (there is a widht "x" of the walkway on each side).
h: 2x+32 (there is a widht "x" of the walkway on each side).
A: 924 ft^2 ( the area of the pool of including the walkway).
2. The area of a rectangle is:
A=(b)(h)
b: the base of the rectangle (2x+16)
a: the height of the rectangle (2x+32)
3. Then, we have a quadratic equation:
924=(2x+16)(2x+32)
4x^2+64x+32x+512-924=0
4x^2+96x-412=0
4. We apply the quadratic formula to find the value of "x":
x=(-b±√(b^2-4ac))/2a
x=3.71
The answer is: The width of the walkway is 3.71 ft
4x____ = 6 so that both sides equal 24
first you find the slope by making using the quation for slope
(7-3)/(0-5) and you find your slope is 4/-5. Then you can plug this into point slope form using on of the coordinates so:
y-y1=m(x-x1) --> y-3=-4/5(x-5)
then you distribute the -1 so -----> y-3=-4/5x+4 and then move the 3 over
so the answer is y= -4/5x+7
