All categories

3 years ago

Help? I’ll give brainliest

Mathematics

1 answer:

Vaselesa [24]3 years ago

4 0

9514 1404 393

Answer:

10,466.7 in^3

Step-by-step explanation:

The volume of a cone is given by ...

V = (1/3)πr^2·h

where r is the radius and h is the height. Using your numbers, we have ...

V = (1/3)(3.14)(20 in)^2·(25 in) = 10,466.7 in^3

_____

A more accurate value of π will give a different result.

You might be interested in

3x - 5 = 10 x = ______

Sphinxa [80]

Answer:

3x - 5 = 10 x

The answer is: $x=-\frac{5}{7}$

Step-by-step explanation:

3x - 5 = 10x

First, Please, Add 5 to both sides, Which would be:

3x - 5 + 5 = 10x + 5

Second, Please, Simplify your answer, Which would be:

3x = 10x + 5

Third, Please, Subtract 10x from both sides, Which would be:

3x - 5 = 10x = 10x + 5 - 10x

Forth, Please, Simplify your answer, Which would be:

-7x = 5

Fifth, Please, Divide both sides by -7, Which would be:

$\frac{-7x}{-7}=\frac{5}{-7}$

Last and Finally, Simplify your answer, Which would be:

$x=-\frac{5}{7}$

I hope I helped :)

5 0

4 years ago

Brainliest if correct

timama [110]

Answer: w = 9

Isolate the variable by dividing each side by factors that don't contain the variable. First, we rearrange the terms.

18 + 4w = 6w

4w + 18 = 6w

Now we subtract 18 from both sides.

When we simplify, we get that w = 9.

Step-by-step explanation:

Hope this helps =)

3 0

3 years ago

Write the following number in decimal notation. Three thousand five hundred and seven hundredths

viktelen [127]

3500.07

I hope this helps!

8 0

4 years ago

Read 2 more answers

The balance of a loan is $2,570 in January, and the monthly payment is $125.50. The relationship between the loan balance, y, an

Hoochie [10]

1600<2570-125.5x<2000 subtract 2570 from all terms...

-970<-125.5x<-570 divide all terms by -125.5 (and reverse signs because of division by a negative!)

7.73>x>4.54 and x is months since January, and since months can only be integers...

x=[5,7]

So January + 5, 6, and 7 respectively are the three months that satisfy the equation...

June, July, and August.

4 0

3 years ago

Read 2 more answers

(sinA-cosA+1)/(sinA+cosA-1)=2(1+cosecA)

borishaifa [10]

Answer:

The trigonometrical expression is sin² A + sin A - 2 cos A - 2 cos A × sin A = 0

Step-by-step explanation:

Given Trigonometrical function as :

$\frac{sin A - cos A + 1}{sin A + cos A - 1}$ = 2 (1 + cosec A)

Or, $\frac{sin A + ( 1 - cos A)}{sin A - (1 - cos A)}$ = 2 (1 + cosec A)

,<u> Now, rationalizing </u>

$\frac{(sin A + ( 1 - cos A)) \times (sin A + (1 - cosA))}{(sin A - (1 - cos A))\times (sin A + (1 - cos A))}$ = 2 (1 + cosec A)

Or, $\frac{(sin A + (1 - cos A))^{2}}{sin^{2} - (1-cos A)^{2}}$ = 2 ( 1 + $\dfrac{1}{\textrm sinA}$

Or, $\frac{sin^{2}A + (1 - cosA)^{2} + 2 \times sin A \times (1 - cos A)}{sin^{2}A - (1 + cos^{2}A - 2 cos A)}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{sin^{2}A + 1 + cos^{2}A - 2 cos A + 2 sin A - 2 sin A cos A}{sin^{2}A - 1 - cos^{2}A +2 cos A}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{sin^{2}A + 1 + cos^{2}A - 2 cos A + 2 sin A - 2 sin A cos A}{sin^{2}A - (sin^{2}A + cos^{2}A) - cos^{2}A +2 cos A}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{2- 2 cos A + 2 sin A - 2 sin A cos A}{- 2cos^{2}A +2 cos A}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{1- cos A + sin A - sin A cos A}{- cos^{2}A + cos A}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{(1- cos A) + sin A (1-cos A)}{cos A(1 - cos A)}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{(1- cos A) (1 + sinA)}{cos A(1 - cos A)}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{(1 + sinA)}{(cos A)}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, sin A + sin² A = 2 cos A (1 + sin A)

Or, sin A + sin² A = 2 cos A + 2 cos A × sin A

Or, sin² A + sin A - 2 cos A - 2 cos A × sin A = 0

So,The trigonometrical expression is sin² A + sin A - 2 cos A - 2 cos A × sin A = 0 Answer

6 0

3 years ago