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Nadusha1986 [10]
3 years ago
15

Jennifer has a beginning balance of $4,750 in her Checking account. After depositing a paycheck (p), she writes a check (c), and

another check (d). After writing the checks, she withdraws money from an ATM (a), then gets refunded some money (r) for returning a pair of shoes she bought. Write an Algebraic Expression that models the situation.
Mathematics
1 answer:
Zepler [3.9K]3 years ago
7 0

Answer:

An Algebraic Expression that models the situation is 4750+p-c-d+r

Step-by-step explanation:

Beginning balance of Jennifer=$4750

Now she deposits a paycheck = p

So, New balance = 4750+p

Now she writes a check = c

Remaining balance = 4750+p-c

Now she writes a check = d

Remaining balance = 4750+p-c-d

Now refunded some money (r) for returning a pair of shoes she bought.

New balance = 4750+p-c-d+r

Hence  an Algebraic Expression that models the situation is 4750+p-c-d+r

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Researchers are studying the distribution of subscribers to a certain streaming service in different populations. From a random
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Answer:

CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}

Step-by-step explanation:

Given

n = 200

x_1 = 34 -- City C

x_2 = 54 --- City K

Required

Determine the 90% confidence interval

This is calculated using:

CI = \bar x \± z\frac{\sigma}{\sqrt n}

Calculating \bar x

\bar x = \bar x_1 - \bar x_2

\bar x = \frac{x_1}{n} - \frac{x_2}{n}

\bar x = \frac{34}{200} - \frac{54}{200}

\bar x = 0.17 - 0.27

For a 90% confidence level, the ​z-score is 1.65.  So:

z = 1.65

Calculating the standard deviation \sigma

\sigma = \sqrt{(\bar x_1)*(1 - \bar x_1) + (\bar x_2)*(1 - \bar x_2) }

So:

\sigma = \sqrt{(0.17)*(1 - 0.17) + (0.27)*(1 - 0.27) }

\sigma = \sqrt{(0.17)*(0.83) + (0.27)*(0.73)}

So:

CI = (0.17 - 0.27)\± 1.65\frac{\sqrt{(0.17)*(0.83) + (0.27)*(0.73)}}{\sqrt {200}}

CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}

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