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Anna71 [15]
3 years ago
7

Divide and simplify 3/4 and 1/2

Mathematics
2 answers:
Maurinko [17]3 years ago
7 0

Answer:

3/2 or 1 1/2

Step-by-step explanation:

Hi,

3/4 divided by 1/2 is the same thing as 3/4 x 2/1. (when dividing fractions, flip the second fraction) When you do this, you simply multiply straight across. So...

3/4 x 2/1 = 6/4

Simplify...

3/2 (both 6 and 4 can be divided by 2)

3/2 = 1 1/2

I hope this helps :)

Fantom [35]3 years ago
3 0

Answer:

1 1/2

Step-by-step explanation:

3/4x2/1=3/2=1 1/2

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Keep the base the same and add your exponents 7^11
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3 years ago
Find the mass of the solid paraboloid Dequals=​{(r,thetaθ​,z): 0less than or equals≤zless than or equals≤8181minus−r2​, 0less th
Lubov Fominskaja [6]

Answer:

M = 5742π  

Step-by-step explanation:

Given:-

- Find the mass of a solid with the density ( ρ ):

                             ρ ( r, θ , z ) = 1 + z / 81

- The solid is bounded by the planes:

                             0 ≤ z ≤ 81 - r^2

                             0 ≤ r ≤ 9

Find:-

Find the mass of the solid paraboloid

Solution:-

- The mass (M) of any solid body is given by the following triple integral formulation:

                           M = \int \int \int {p ( r ,theta, z)} \, dV\\\\

- We can write the above expression in cylindrical coordinates:

                           M = \int\limits\int\limits_r\int\limits_z {r*p(r,theta,z)} \, dz.dr.dtheta \\\\M = \int\limits\int\limits_r\int\limits_z {r*[ 1 + \frac{z}{81}] } \, dz.dr.dtheta\\\\

- Perform integration:

                           M = \int\limits\int\limits_r{r*[ z + \frac{z^2}{162}] } \,|_0^8^1^-^r^2 dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + \frac{(81-r^2)^2}{162}] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + \frac{6561 -162r + r^2}{162}] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + 40.5 -r +\frac{r^2}{162} ] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{[ 121.5r-r^2 -\frac{161r^3}{162} ] } \, dr.dtheta\\\\

                           M = 2*\int\limits_0^\pi {[ 121.5r^2-r^3 -\frac{161r^4}{162} ] } |_0^6 \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 121.5(6)^2-(6)^3 -\frac{161(6)^4}{162} ] }  \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 4375-216 -1288] }  \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 2871] }  \, dtheta\\\\M = 5742\pi  kg              

- The mass evaluated is M = 5742π                      

8 0
3 years ago
Jackie followed these steps to evalute the expression
sweet [91]

??? what steps are you talking about. lol

6 0
3 years ago
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3 0
3 years ago
Read 2 more answers
Find the slope(-1,-1),(2,-2)
Natali [406]

Answer:

\huge\boxed{slope=-\dfrac{1}{3}}

Step-by-step explanation:

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

Substitute the coordinates of the given points (-1, -1) and (2, -2):

m=\dfrac{-2-(-1)}{2-(-1)}=\dfrac{-2+1}{2+1}=\dfrac{-1}{3}=-\dfrac{1}{3}

5 0
3 years ago
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