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4 years ago

Find the difference and express the answer in scientific notation. (9.1 x 10^6) - (8.9 x 10^6)

Mathematics

2 answers:

RSB [31]4 years ago

4 0

Answer:

200000x

Step-by-step explanation:

mr Goodwill [35]4 years ago

4 0

The Actual Answer Is -- A.) 2.0 × 10–7 --

2020

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lina2011 [118]

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You have to put an attachment file of the options or what x equals.

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3 years ago

What fraction of 60 is 90? 50 POINTS OwO

maxonik [38]

Step-by-step explanation:

90 / 60 = 3/2

When you multiply 3/2 with 60, you get 90.

Hence 3/2 of 60 is 90.

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3 years ago

PLZ HELP FAST shsggsgsgsbdfikand

OLga [1]

Answer:

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The domain is 1,2,3,4 it would be from 1 to 4 if the electrician bills for partial hours, or greater than 4, but this is not in the chart.

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3 years ago

What is the kinetic energy of a 14 kg mass moving with a velocity of 3 m/s? 1 point

aleksandr82 [10.1K]

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3 years ago

In a random sample of 10 residents of the state of Washington, the mean waste recycled per person per day was 2.3 pounds with a

djverab [1.8K]

Answer:

90% confidence interval for the mean waste recycled per person per day for the population of Washington is [2.074 , 2.526].

Step-by-step explanation:

We are given that a a random sample of 10 residents of the state of Washington, the mean waste recycled per person per day was 2.3 pounds with a standard deviation of 0.39 pounds.

Firstly, the pivotal quantity for 90% confidence interval for the mean waste recycled per person per day for the population of Washington is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean waste recycled per person per day = 2.3 pounds

s = sample standard deviation = 0.39 pounds

n = sample of residents = 10

$\mu$ = population mean waste recycled per person per day

Here for constructing 90% confidence interval we have used t statistics because we don't know about population standard deviation.

So, 90% confidence interval for the population mean, $\mu$ is ;

P(-1.833 < $t_9$ < 1.833) = 0.90 {As the critical value of t at 9 degree of

freedom are -1.833 & 1.833 with P = 5%}

P(-1.833 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 1.833) = 0.90

P( $-1.833 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $1.833 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

P( $\bar X-1.833 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.833 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

90% confidence interval for $\mu$ = [ $\bar X-1.833 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.833 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $2.3-1.833 \times {\frac{0.39}{\sqrt{10} } }$ , $2.3-1.833 \times {\frac{0.39}{\sqrt{10} } }$ ]

= [2.074 , 2.526]

Therefore, 90% confidence interval for the mean waste recycled per person per day for the population of Washington is [2.074 , 2.526].

8 0

3 years ago