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Nata [24]
3 years ago
10

Julie rented a car for one day from a company that charges $80 per day plus $0.15 per mile driven. If she was charged a total of

$98 for the rental and mileage, for how many miles of driving was Julie charged? (assume there is no tax)
Mathematics
2 answers:
Studentka2010 [4]3 years ago
4 0

Answer: 5

Step-by-step explanation:

Pani-rosa [81]3 years ago
3 0
98-80=18
18/0.15=120
Julie was charged 120 miles
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Two friends share 7 cookies how many cookies do each of them get
Goshia [24]

Answer:

3.5 cookies

Step-by-step explanation:

Hi there!

Well, assuming they get the same amount of cookies, you'd do 7/2..

7/2=3.5

So they'd each get 3.5 cookies.

Have a great day! ^u^

7 0
3 years ago
Can someone please help me its the second time im asking this
scoundrel [369]

Answer:

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8 0
1 year ago
If y= 3x + 6, what is the minimum value of (x^3)(y)?
Rainbow [258]

Answer:

Given the statement: if y =3x+6.

Find the minimum value of (x^3)(y)

Let f(x) = (x^3)(y)

Substitute the value of y ;

f(x)=(x^3)(3x+6)

Distribute the terms;

f(x)= 3x^4 + 6x^3

The derivative value of f(x) with respect to x.

\frac{df}{dx} =\frac{d}{dx}(3x^4+6x^3)

Using \frac{d}{dx}(x^n) = nx^{n-1}

we have;

\frac{df}{dx} =(12x^3+18x^2)

Set \frac{df}{dx} = 0

then;

(12x^3+18x^2) =0

6x^2(2x + 3) = 0

By zero product property;

6x^2=0   and 2x + 3 = 0

⇒ x=0 and x = -\frac{3}{2} = -1.5

then;

at x = 0

f(0) = 0

and  

x = -1.5

f(-1.5) = 3(-1.5)^4 + 6(-1.5)^3 = 15.1875-20.25 = -5.0625


Hence the minimum value of (x^3)(y) is, -5.0625






3 0
3 years ago
Evaluate the expression when a= 2 and c=-4.<br> -a +5c
-Dominant- [34]
The answer would be 18
4 0
3 years ago
Solve the following equation
Veronika [31]
The answer to the equation is x=4.5
7 0
3 years ago
Read 2 more answers
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