You say that there is uniform acceleration so:
vf-vi=at (final velocity minus initial velocity is equal to acceleration times time)
We know vf, vi, and t so we can solve for acceleration:
24-12=a10
12=10a
a=1.2
That is the acceleration, we will need to integrate with respect to time twice...
v=⌠a dt
v=at+vi , we know a=1.2m/s^2 and vi=12m/s
v=1.2t+12,
x=⌠1.2t+12 dt
x=1.2t^2/2+12t+xo, we can just let xo=0 for this problem...
x(t)=0.6t^2+12t
Now we know that this acceleration lasts for 10 seconds so the distance traveled in that time is:
x(10)=0.6(10^2)+12(10)
x(10)=60+120
x(10)=180 meters
Step-by-step explanation:
We must ask a question that your answer corresponds to each of the topics in the statement, therefore we will review each one:
5. Distances members of the track team jogged last week
How far did you run last week?
6. Numbers of letters in name of street you live on
How many letters are there in the name of your street?
7. Cost of a restaurant dinner
How much did you pay for dinner?
8. Numbers of cars of different colors in a parking lot
What color is your car?
126 + 9x = 180
180 - 126 = 54
9x = 54
x = 6
mark me brainliest if the answer is correct , thank you in advance :)
Step-by-step explanation:
3x - y = 74
4y = x
Replace x in the first expression by 4y
3x - y = 74 ➡ 3(4y) - y = 74
12y - y = 74
11y = 74
y = 74/11 we can use this to find x
4y = x
4 × 74/11 = x
296/11 = x
Answer:
option A
Step-by-step explanation:
We can find the standard form by expanding the equation:
y = 3(x-4)^2 - 22
y = 3(x^2 - 8x + 16) - 22
y = 3x^2 - 24x + 48 - 22
y= 3x^2 - 24x + 26
So the correct option is option A
