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DaniilM [7]
3 years ago
11

the sum of a number and 5,multiplied by 10 i don't know how to translate a verbal equation to an algebradic expression

Mathematics
2 answers:
mel-nik [20]3 years ago
6 0
10(x+5) this is the answer
Furkat [3]3 years ago
5 0
Let the number be x.

Sum of the number and 5 is = (x + 5)

Multiplied by 10 = 10*(x + 5)

So it translates to 10*(x + 5)

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The points in the table lie on a line. Find the slope of the line
NikAS [45]

Answer:

4

Step-by-step explanation:

(y2-y1)/(x2-x1)=m

(10-2)/(3-1)

8/2

m=4

3 0
2 years ago
You've just purchased 12 lb of celery. You take it back to your kitchen and proceed to trim and cut it into pieces, ending up wi
Alecsey [184]
We should know that ⇒ 1 lb = 16 oz

The amount of purchased celery = 12 lb = 12 * 16 = 192 oz
<span>Trim and cut it into pieces, ending up with 5.5 oz of trim.
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</span><span>The yield will be = 192/5.5 = 34.91
</span><span>
</span><span>Taking the smallest integer number.
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</span><span>So, the yield = 34
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</span><span>which will be equal = 34*5.5 = 187 oz
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</span><span>So, the yield </span>percentage = \frac{187}{192} *100 = 97.4 \%
3 0
3 years ago
If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?
lys-0071 [83]

Answer:

2

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

3x^2-(3k-2)x-(k-6) \text{ with }k=2:

3x^2-(3\cdot 2-2)x-(2-6)

3x^2-4x+4

I'm going to solve 3x^2-4x+4=0 for x using the quadratic formula:

\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}

\frac{4\pm \sqrt{16-16(3)}}{6}

\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}

\frac{4\pm 4\sqrt{-2}}{6}

\frac{2\pm 2\sqrt{-2}}{3}

\frac{2\pm 2i\sqrt{2}}{3}

Let's see if uv=u+v holds.

uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}

Keep in mind you are multiplying conjugates:

uv=\frac{1}{9}(4-4i^2(2))

uv=\frac{1}{9}(4+4(2))

uv=\frac{12}{9}=\frac{4}{3}

Let's see what u+v is now:

u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}

u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}

We have confirmed uv=u+v for k=2.

4 0
3 years ago
Solve the equation for the value of x; 8x + 12 = 52.
777dan777 [17]
The answer is c: x=5
7 0
3 years ago
Read 2 more answers
Pls answer me ill give points and brainlest​
Elodia [21]

Answer:

Sorry is there any more information i will then change answer

Step-by-step explanation:

7 0
3 years ago
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