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2 years ago

Find the unit rate. Kenny reads 58 page in 23 minute. how many pages Kenny reads per minute

Mathematics

1 answer:

lora16 [44]2 years ago

7 0

Answer:

Step-by-step explanation:

The unit rate is pages per minute, so divide the pages by the minutes: (5/8)/(2/3) = (5/8)·(3/2) = 15/16 pages per minute

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Given a polynomial function f(x), describe the effects on the y-intercept, regions where the graph is increasing and decreasing,

Jobisdone [24]

A. When f(x) becomes g(x) = f(x) + 2, the graph of f(x) is shifted upward 2 units.

B The graph of f(x) is reflected in the x-axis and then vertically compressed by a factor of 1/2.

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3 years ago

24-4x=2x<br> show your work, will mark brainliest

vladimir2022 [97]

Answer:

x=4

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

24−4x=2x

24+−4x=2x

−4x+24=2x

Step 2: Subtract 2x from both sides.

−4x+24−2x=2x−2x

−6x+24=0

Step 3: Subtract 24 from both sides.

−6x+24−24=0−24

−6x=−24

Step 4: Divide both sides by -6.

−6x /−6 = −24 /−6

x=4

5 0

2 years ago

Read 2 more answers

What is the difference between points F (2,9) and G (4,14) round to the nearest whole number.

Sonbull [250]

Answer:

3,15

Step-by-step explanation:

took the test boi

7 0

2 years ago

How do I find point-slope form???

Nana76 [90]

I believe the answer is: By using the point slope formula, which states that a given point (x1, y1) and a slope m, the equation of the line can be written as y - y1 = m(x - x1)

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2 years ago

In a recent year, Washington State public school students taking a mathematics assessment test had a mean score of 276.1 and a s

Oksi-84 [34.3K]

Answer:

a) $\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

b) From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

c) $P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

$P(Z\geq2.070)=1-P(Z$

Step-by-step explanation:

Let X the random variable the represent the scores for the test analyzed. We know that:

$\mu=E(X) = 276.1 , \sigma=Sd(X) = 34.4$

And we select a sample size of 64.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

For this case the mean and standard error for the sample mean would be given by:

$\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

Part b

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

Part c

For this case we want this probability:

$P(\bar X \geq 285)$

And we can use the z score defined as:

$z=\frac{\bar x -\mu}{\sigma_{\bar x}}$

And using this we got:

$P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

And using a calculator, excel or the normal standard table we have that:

$P(Z\geq2.070)=1-P(Z$

8 0

2 years ago