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jarptica [38.1K]
2 years ago
5

Plz plz plz help plz i need help

Mathematics
2 answers:
nadezda [96]2 years ago
6 0

Answer:

62/10

Step-by-step explanation:

All the other options are positive integers, which are natural numbers.

Viktor [21]2 years ago
3 0

Answer:

\frac{62}{10}

is a fraction which isn't a natural number,

and

\frac{40}{4}

can be simplified to get 10, which is natural number and others are natural numbers too

62/10 is not a natural number

correct option A

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3 years ago
he life of light bulbs is distributed normally. The variance of the lifetime is 625 and the mean lifetime of a bulb is 540 hours
almond37 [142]

Using the normal distribution, it is found that there is a 0.877 = 87.7% probability of a bulb lasting for at most 569 hours.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 540, \sigma = \sqrt{625} = 25

The probability of a bulb lasting for at most 569 hours is the <u>p-value of Z when X = 569</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{569 - 540}{25}

Z = 1.16

Z = 1.16 has a p-value of 0.877.

0.877 = 87.7% probability of a bulb lasting for at most 569 hours.

More can be learned about the normal distribution at brainly.com/question/24663213

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