We have two points so we can find the gradient using y1-y2/x1-x2
gradient = 21-27/2-8
= 1
we know the form for any linear equation is y = mx + c
we have m and a point so we can substitute in point (2,21) to find c
21 = 1 x 2 + c
c = 19
therefore, the equation is y = x + 19
1/6 x 54 = 9
Hope this helps ;)
A=a+b/2·h=9+4/2·3.5=22.75
Hoped I helped!
