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3 years ago

Please help me I need an urgent help

Mathematics

1 answer:

andreev551 [17]3 years ago

3 0

Answer:

9. € 29.00

10. $ 15.3

11.total meters = 6 timbers × 3.9 m

total meters = 6 timbers × 3.9 m = 23. 4 meters

total meters = 6 timbers × 3.9 m = 23. 4 metersextra meter he needs = (25 - 23.4) m

total meters = 6 timbers × 3.9 m = 23. 4 metersextra meter he needs = (25 - 23.4) m = 1.6 m

12.

a. Total mass of pies, 5700 × 0.26kg = 1,482kg

b. Total mass of pasties , 3600× 0.26kg = 936kg

c. total mass of pies and pasties =( 3600× 0.26+ 5700× 0.26) kg = 2418kg

d. the number of heated vans = 2418kg/500

the number of heated vans = 2418kg/500 = 4.836kg is almost 5 vans

Step-by-step explanation:

9. He needs 0.4 m³ of concrete

1 m³ concrete costs €72.50

0.4m³ = x

we represent x buy the cost of concrete he'll need since we don't know

we cross multiply,

1 m³ = 72.50

0.4 = x

x = 72.50 × 0.4

x = € 29.00

10. 1 meter of hose = $ 3. 40

4.5 meter of hose = x

we cross multiply,

X= $ 15.3

11. 6 timbers, each has 3.9 m long

total meters = 6 timbers × 3.9 m

= 23. 4 meters

extra meter he needs = (25 - 23.4) m

= 1.6 m

12. 5700 pies, each has mass of 0.26kg

3600 pasties, each had mass of 0.26kg

a. Total mass of pies, 5700 × 0.26kg = 1,482kg

b. Total mass of pasties , 3600× 0.26kg = 936kg

c. total mass of pies and pasties

=( 3600× 0.26+ 5700× 0.26) kg

= 2418kg

d. the total mass of the pies and pasties is 2418kg

each heated van weighs 500kg

the number of heated vans = 2418kg/500

= 4.836kg is almost 5 vans

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