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Mashutka [201]
3 years ago
11

For which values of k does the system of linear equations have zero, one, or an infinite number of solutions? [Note: not all thr

ee possibilities need occur.] (If the answer is an interval of numbers, enter your answer using interval notation. If an answer does not exist, enter DNE.) 3x1 − x2 = 2 9x1 − 3x2 = k
Mathematics
1 answer:
viktelen [127]3 years ago
4 0

Answer:

The system has an infinite solution at k = 6, otherwise for any value of k, it has zero solution.

Step-by-step explanation:

Consider the system of linear equations:

3x_{1} -x_{2}=2\;\;\;\;\;\;(1)\\ 9x_{1} -3x_{2}=k\;\;\;\;\;(2)

The system of linear equations can have zero, one, or an infinite number of solutions:

simplify equation (1):

x_{2}=3x_{1} -2

substitute in equation (2), we get

9x_{1} -3(3x_{1}-2)=k\\9x_{1} -9x_{1}+6=k\\0+6=k

we cannot find the value of x_{1} and x_{2}.

so, there is no solution.

Multiply the equation (1) with 3 and put k is 6,

3(3x_{1} -x_{2})=3\times2\\9x_{1} -3x_{2})=6

it means both equations are overlapped. Then, the solution has infinite solutions.

Hence, the system has an infinite solutions at k is 6 otherwise for any value of k it has no solution.

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