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andreev551 [17]
3 years ago
6

Walman Corp. manufactures products X, Y, and Z from a joint production process. Joint costs are allocated to products on the bas

is of relative sales value at the split-off point. Additional information is as follows: X Y Z Total Units produced 14,000 10,000 6,000 30,000 Joint costs $204,000 $90,000 $66,000 $360,000 Sales value at split-off ? 150,000 110,000 600,000 Additional costs for further processing 38,000 30,000 22,000 90,000 Sales value if processed further 348,000 185,000 147,000 680,000 Based solely on a relevant cost analysis, which of the three products should be manufactured by Walman beyond the split-off point?
Business
1 answer:
rewona [7]3 years ago
3 0

Answer:

We will only produce further product Y and Z

Explanation:

We should check the increase in sales revenue with the increase in cost to know if further process acheive a gain:

<u>Product X</u>

Increase in sales value:

348,000 - 340,000 =  8,000

Additional Cost:     <u>   (38,000)  </u>

difference:                 (30,000) Non-profitable

<u>Product Y</u>

Increase in sales revenue:

185,000 - 150,000 =  35,000

additional cost:      <u>   (30,000)  </u>

difference:                   5,000 Profitable

<u>Product Z</u>

Increase in sales revenue:

147,000 - 110,000 =   37,000

additional cost:    <u>    (22,000)   </u>

difference:                 15,000 Profitable

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A company has a selling price of $1,800 each for its printers. Each printer has a 2 year warranty that covers replacement of def
Afina-wow [57]

Answer:

$90,000

Explanation:

Data given in the question

Selling price = $1,800

Estimated percentage = 2%

Average cost = $150

Number of printers sold = 30,000

Under the warranty, the printer under service = 400

So by considering the above information, the warranty expense is

= Number of printers sold × estimated percentage × average cost per printer

= 30,000 × 2% × $150

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8 0
3 years ago
Each machine must be run by one of 19 cross-trained workers who are each available 35 hours per week. The plant has 10 type 1 ma
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Answer:

The Linear programming model is given as below

Profit Function: P=90X+120Y+150Z

Constraints:

2X+2Y+Z\leq 400

3X+4Y+6Z\leq 240

4X+6Y+5Z\leq 320

\dfrac{2X+2Y+Z}{40}\leq 10

\dfrac{3X+4Y+6Z}{40}\leq 6

\dfrac{4X+6Y+5Z}{40}\leq 8

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

Explanation:

As the question is not complete, the complete question is found online and is attached herewith.

Let the number of product 1 to be produced is X, that of product 2 is Y and product 3 is Z

so  the maximizing function is the profit function which is given as

P=90X+120Y+150Z

Now as the number of hours in a week are 40 and there are a total of 10 type 1 machines so the total number of machine 1 hours are 40*10=400 hours

As from the given table product 1 uses 2 machine hours of machine 1, product 2 uses 2 machine hours of machine 1 and product 3 uses 1 hour of machine 1 so

2X+2Y+Z\leq 400

Now as the number of hours in a week are 40 and there are a total of 6 type 2 machines so the total number of machine 2 hours are 40*6=240 hours

As from the given table product 1 uses 3 machine hours of machine 2, product 2 uses 4 machine hours of machine 2 and product 3 uses 6 hour of machine 2 so

3X+4Y+6Z\leq 240

Now as the number of hours in a week are 40 and there are a total of 8 type 3 machines so the total number of machine 3 hours are 40*8=320 hours

As from the given table product 1 uses 4 machine hours of machine 3, product 2 uses 6 machine hours of machine 3 and product 3 uses 5 hour of machine 3 so

4X+6Y+5Z\leq 320

Now as the machine 1 is used as 2X+2Y+Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{2X+2Y+Z}{40}\leq 10

Now as the machine 2 is used as 3X+4Y+6Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{3X+4Y+6Z}{40}\leq 6

Now as the machine 3 is used as 4X+6Y+5Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{4X+6Y+5Z}{40}\leq 8

Now the workers are available for 35 hours so the worker available at the machine 1 is given as

\dfrac{2X+2Y+Z}{35}

That of machine 2 is given as

\dfrac{3X+4Y+6Z}{35}

That of machine 3 is given as

\dfrac{4X+6Y+5Z}{35}

As the total number of workers is 19 so the constraint is given as

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

So the Linear programming model is given as below

Profit Function: P=90X+120Y+150Z

Constraints:

2X+2Y+Z\leq 400

3X+4Y+6Z\leq 240

4X+6Y+5Z\leq 320

\dfrac{2X+2Y+Z}{40}\leq 10

\dfrac{3X+4Y+6Z}{40}\leq 6

\dfrac{4X+6Y+5Z}{40}\leq 8

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

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b. The EITC provides greater benefits as low-income workers earn more income (up to a point).

<u>True</u>

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