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3 years ago

Find the area of a regular hexagon with the side length of 10 centimeters. Round to the nearest tenth

1 answer:

8 0

Polygon area = n * side length^2 / 4 * tan(180/n)
where "n" = number of sides
hexagon area = 6 * 10^2 / 4 * tan(180/6)
hexagon area = 600 / 4 * tan(30)
hexagon area = 600 / 4 * 0.57735
hexagon area = 259.8077422707 square centimeters
hexagon area = 259.8 square centimeters

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What is 1.5 as a ratio

Kitty [74]

Answer: 3/2

Step-by-step explanation:

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3 years ago

MLON is a straight angle. mMON = 8x - 13 mLOM = 7x – 17° Find MON

Morgarella [4.7K]

Answer:MON=99

Step-by-step explanation:

8x-13+7x-17=180

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3 years ago

Read 2 more answers

during one month the orangevale parks and recreation district spent $5720 for various activities. they spent $1430 on mommy and

AysviL [449]

To solve this problem, we must figure out what percent of the total spending was spent on mommy and baby exercise programs. To figure this out, we should divide how much was spent on the mommy and baby exercise by the total amount spent on the district activities.

$1430/$5720 = 0.25

This is a percentage, or a portion out of 100, which means we must multiply this decimal by 100 to find its equivalent percentage.

0.25 * 100 = 25

Therefore, your answer is 25% of the total spending was spent on mommy and baby exercise programs.

Hope this helps!

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3 years ago

Describe how the graph of the function g(x) = -5x²-2 is related to the graph of

zhenek [66]

Answer:

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2 years ago

Assume that adults were randomly selected for a poll. They were asked if they "favor or oppose using federal tax dollars to fund

ser-zykov [4K]

Testing the hypothesis, it is found that since the p-value of the test is 0.0042 < 0.01, it can be concluded that the proportion of subjects who respond in favor is different of 0.5.

At the null hypothesis, it is tested if the proportion is of 0.5, that is:

$H_0: p = 0.5$

At the alternative hypothesis, it is tested if the proportion is different of 0.5, that is:

$H_1: p \neq 0.5$

The test statistic is given by:

$z = \frac{\overline{p} - p}{\sqrt{\frac{p(1 - p)}{n}}}$

In which:

$\overline{p}$ is the sample proportion.
p is the value tested at the null hypothesis.
n is the sample size.

In this problem, the parameters are given by:

$p = 0.5, n = 483 + 398 = 881, \overline{p} = \frac{483}{881} = 0.5482$

The value of the test statistic is:

$z = \frac{\overline{p} - p}{\sqrt{\frac{p(1 - p)}{n}}}$

$z = \frac{0.5482 - 0.5}{\sqrt{\frac{0.5(0.5)}{881}}}$

$z = 2.86$

Since we have a two-tailed test(test if the proportion is different of a value), the p-value of the test is P(|z| > 2.86), which is 2 multiplied by the p-value of z = -2.86.

Looking at the z-table, z = -2.86 has a p-value of 0.0021.

2(0.0021) = 0.0042

Since the p-value of the test is 0.0042 < 0.01, it can be concluded that the proportion of subjects who respond in favor is different of 0.5.

A similar problem is given at brainly.com/question/24330815

3 0

3 years ago