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3 years ago

PLEASE ANSWER:

2 answers:

6 0

For number one, i believe it would be 6x + 15Y-12. You just multiply 3 by everything i. the parentheses. I hope this helps :)

34kurt3 years ago

4 0

Answer:

1. 6x+15y-12

2. 25

3. 5(11x-5)

Step-by-step explanation:

1. We have the expression $3(2x+5y-4)$ we have to distribute number 3 to simplify the expression:

$3(2x+5y-4)=\\3.(2x)+3.(5y)-3.(4)=\\=6x+15y-12$

Then the correct answer is the first choice: 6x+15y-12

2. We have to find the value of the expression when c=4, we have

$f(c)=4c + 3c -2c + 5$

Then when c=4:

$f(4)=4.(4) + 3.(4) -2.(4)+ 5\\f(4)=16+12-8+5\\f(4)=28-3\\f(4)=25$

Then the correct answer is the first choice: 25

3. We have to factor the expression 55x-25,

we can see that (5).11=55 and (5).5=25, then the common factor in this expression is number 5,

$55x-25=\\(5).11x-(5).5=\\=5(11x-5)$

Then the correct answer is the first choice: 5(11x-5)

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Find the values of X and Y. Write your answers in simplest form. X=__ Y=__

uranmaximum [27]

Hope this helps!
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8 0

3 years ago

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Answer:

The amount lost over the 3 years s 2567.25£

Explanation:

$\mathrm{F}=\mathrm{I} \times\left(1-\left(\frac{r}{100}\right)\right)^{\mathrm{n}}$

where F = final value after n years

I = initial value of the car in 2017 = £18000 (given)

Since the value is depreciated 5% every year for 3 years,

r = percentage rate of depreciation = 5% (given)

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Substituting these values in formula, we get

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= 15432.75£ which is the value of the car after 3 years

Finally 18000-15432.75 = 2567.25£ is the amount lost over this period.

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3 years ago

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Soloha48 [4]

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3 years ago

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First
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