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vagabundo [1.1K]
3 years ago
15

Will's band played 33 shows in three months. How many shows per month did they play?

Mathematics
1 answer:
GrogVix [38]3 years ago
5 0

Answer:

11

Step-by-step explanation:

33÷3= 11

11 shows every month

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David Howell was shopping for a leather jacket. He found one at the department store that was selling for $395. He learned that
Firlakuza [10]
David Howell was shopping for a leather jacket and found one on the dept. store that costs 395 dollars.
Now, he learned that an inflation rate of 4.5% has occurred since the jacket was originally priced.
=> 395 dollars * .045 = 17.775
=> 395 dollars - 17.775  = 377.23 is the original price of the jacket.
3 0
4 years ago
Write the reciprocal of<br> 13
Masteriza [31]

Answer:

Likewise the reciprocal of 13 is 3 and so on.

Step-by-step explanation:

To find the reciprocal of any number, just calculate "1 ÷ (that number)." For a fraction, the reciprocal is just a different fraction, with the numbers "flipped" upside down (inverted). For instance, the reciprocal of 3/4 is 4/3. Any number times its reciprocal will give you 1.

4 0
3 years ago
Read 2 more answers
There are 360 seals. Of them are 9/20 are pups. The rest are adult seals . How many pups are the beach .
k0ka [10]

Answer:

162 pups are on the beach

Step-by-step explanation:

9/20 of 360

The key word "of" tells us to multiply

Variable x = number of pups

9/20 × x/360

Cross multiply

9 × 360 = 20 × x

3,240 = 20x

Divide both sides by 20

162 = x

Check our work:

9/20 = 162/360

Cross multiply

9 × 360 = 20 × 162

3,240 = 3,240

Correct

3 0
3 years ago
Alice used a $250 cash advance from her credit card company to get cash while on a trip. The company charges a daily finance fee
11111nata11111 [884]

you do 0.047×40 and what ever that gives you you add it to 40 and it will give you the answer

6 0
3 years ago
85.87 J or heat energy is added to a 34.8 g mass of substance the temperature rises from 21.76°C
Andru [333]

Answer:

The required specific heat is 196.94 joule per kg per °C  

Step-by-step explanation:

Given as :

The heat generated = Q = 85.87 J

Mass of substance  (m)= 34.8 gram = 0.0348 kg

Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C

Let the specific heat = S

Now we know that

Heat = Mass × specific heat × change in temperature

Or, Q = msΔt

Or, 85.87 = (0.0348 kg ) × S × 12.53°C

Or , 85.87 = 0.4360 × S

Or, S = \frac{85.87}{0.4360}

∴ S = 196.94 joule per kg per °C

Hence the required specific heat is 196.94 joule per kg per °C   Answer

7 0
3 years ago
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