Neither. When graphing both lines they intersect but are not perpendicular.
Mimiwhatsup Answer is: H
The graph is correct and so is the table it's domain and ranges are correct I know I is not correct hope this helps!
Answer:
1080 m^2 Don't submit m^2 in your answer.
Step-by-step explanation:
Givens
The catch is to find h
To do that, use a^2 + b^2 = c^2
a b and c are in the same 1/2 triangle.
a = 48/2 = 24 m
b = h = ?
c = 51 meters
Solution
a^2 + b^2 = 51^2 Substitute for b^2 = h^2
24^2 + h^2 = 51^2 Expand 24^2 and 51^2
576 + h^2 = 2601 Subtract 576 from both sides
h^2 = 2601 - 576
h^2 = 2025 Take the square root of both sides
h = 45
Area
Area = 1/2 b * h
Area = 1/2 48 * 45
Area = 1080
Remark
Notice that to find h you only use 1/2 of 48 because that is the base of the right triangle.
To find the area, you need to use all of 48 because 48 is the full length of the base.
Answer: D
<u>Step-by-step explanation:</u>
The first matrix contains the coefficients of the x- and y- values for both equations (top row is the top equation and the bottom row is the bottom equation. The second matrix contains what each equation is equal to.
![\begin{array}{c}2x-y\\x-6y\end{array}\qquad \rightarrow \qquad \left[\begin{array}{cc}2&-1\\1&-6\end{array}\right] \\\\\\\begin{array}{c}-6\\13\end{array}\qquad \rightarrow \qquad \left[\begin{array}{c}-6\\13\end{array}\right]](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bc%7D2x-y%5C%5Cx-6y%5Cend%7Barray%7D%5Cqquad%20%5Crightarrow%20%5Cqquad%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-1%5C%5C1%26-6%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%5C%5C%5Cbegin%7Barray%7D%7Bc%7D-6%5C%5C13%5Cend%7Barray%7D%5Cqquad%20%5Crightarrow%20%5Cqquad%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D-6%5C%5C13%5Cend%7Barray%7D%5Cright%5D)
The product will result in the solution for the x- and y-values of the system.
