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2 years ago

6+4×5-5² help please I keep on getting 16

Mathematics

2 answers:

larisa86 [58]2 years ago

4 0

Answer:

Step-by-step explanation:

You perform the exponential and multiplication first:

6 + 4 x 5 - 5^2

= 6 + 20 - 25

= 26 - 25

= 1.

Whitepunk [10]2 years ago

3 0

Answer: 1

Step-by-step explanation:

6+4×5-5²

=6+20-25

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The height of a triangle is 5 cm shorter than its base. If the area of the triangle is 25 cm2, find the height of the triangle.

Olin [163]

Answer:

$h = 5\ cm$

Step-by-step explanation:

Let's call B at the base of the triangle and call h at the height of the triangle. Then we know that:

The height of a triangle is 5 cm shorter than its base. This means that:

$h = B-5$ .

The area of the triangle is 25 cm²

By definition the area of a triangle is:

$A = 0.5Bh$

For this triangle we know that $A = 25\ cm^2$ and $h = B-5$ . We substitute these values in the equation and solve for B.

$25 = 0.5B (B-5)$

$0.5B ^ 2-\frac{5}{2}B-25 = 0$

Now we use the quadratic formula to solve the equation.

For an equation of the form $ax ^ 2 + bx + c = 0$ the quadratic formula is:

$B=\frac{-b\±\sqrt{b^2-4ac}}{2a}$

In this case note that: $a=0.5,\ \ b=-\frac{5}{2}\ \ c=-25$

Then:

$B=\frac{-(-\frac{5}{2})\±\sqrt{(-\frac{5}{2})^2-4(0.5)(-25)}}{2(0.5)}$

$B=\frac{\frac{5}{2}\±\sqrt{\frac{25}{4}+50}}{1}$

$B=\frac{5}{2}\±\frac{15}{2}$

The solutions are:

$B_1=\frac{5}{2}+\frac{15}{2}=10$

$B_2=\frac{5}{2}-\frac{15}{2}=-5$

For this problem we take the positive solution.

$B=10\ cm$

Now we substitute the value of B in the equation to find the height h

$h = 10-5$

$h = 5\ cm$

6 0

2 years ago

Help help help help help

sdas [7]

Draw out a number line with the values 0, 5, 10, 15, 20, 25, 30, etc (basically multiples of 5)

Then plot a point at 25

-----------------

Or you can draw out a number line with the multiples of 10, so with the values 0, 10, 20, 30, ...

Then plot a point at the exact midway point between 20 and 30 to represent the value 25

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3 years ago

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LKM≈TEJ since it makes the triangles congruent, although the angles in each triangle are not corresponding equal angles

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Step-by-step explanation:

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