i believe this is the answer n(2)-7<span />
There are the combinations that result in a total less than 7 and at least one die showing a 3:
[3, 3] [3,2] [2,1] [1,3] [2,3]
The probability of each of these is 1/6 * 1/6 = 1/36
There is a little ambiguity here about whether or not we should count [3,3] as the problem says "and one die shows a 3." Does this mean that only one die shows a 3 or at least one die shows a 3? Assuming the latter, the total probability is the sum of the individual probabilities:
1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 5/36
Therefore, the required probability is: 5/36
If found the image that accompanies this problem, the central angle was 60°. Since the circumference of a circle is always 360°, the minor arc represents 60°/360° of the circle.
48 cm / (60°/360°) = 48 cm / (1/6) = 48 cm * 6/1 = 48 cm * 6 = 288 cm
The circumference of circle Z is 288 cm.
Look like whatever <span>3.5×2</span> is. (7)
Answer:
809 km²
Step-by-step explanation:
I can split this into 3 rectangles. One is 25 by 17, another is 24 by 13, and the last one is 6 by 12. (I had gotten 13 for the second rectangle because 25 - 12 = 13.)
(25 * 17) + (24 * 13) + (6 * 12) <em>{17 is the first number after a multiple of 4 (16). As a result, 25 by 17 will end in "25." 25 by 17 is 425.}</em>
425 + (24 * 13) + (6 * 12) <em>{24 by 13 is 312.}</em>
425 + 312 + (6 * 12) <em>{6 by 12 is 72.}</em>
425 + 312 + 72 <em>{From left to right, add 425, 312, and 72 to get 809}</em>
737 + 72
809 km²
The area of this figure is 809 km².
