Answer:
<h2>894 mi²</h2>
Step-by-step explanation:
First, let's view the formula which we will use to solve this problem. The area of a parallelogram is: A = bh. A is the area, b is the base, h is the height.
A = bh
Insert the values
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Answer:
The formulas for converting between degree Celsius and degree Fahrenheit are:
°F = (°C * 9/5) + 32
°C = (°F - 32) * 5/9
To find the temperature when both are equal, we use an old algebra trick and just set ºF = ºC and solve one of the equations.
°C = (°C * 9/5) + 32
°C - (°C * 9/5) = 32
-4/5 * °C = 32
°C = -32 * 5/4
°C = -40
°F = (°F * 9/5) + 32
°F - (°F * 9/5) = 32
-4/5 * °F = 32
°F = -32 * 5/4
°F = -40
So the temperature when both the Celsius and Fahrenheit scales are the same is -40 degrees
Have a nice day!!!
Answer:
87 degrees
Step-by-step explanation:
The triangle with the angles 79 and 15, we can find the last value because all angles in a triangle add up to 180. So, 180-79-15= 86 degrees for the angle of the triangle.
Because the 86 degree angle is complimentary, or when added up to the adjacent angle, is 90 degrees (we see that little box sign), that means that 90-86=4 degrees for the upper triangle in the angle that isn't the question mark. Now that we know 2 values for the top triangle, we can solve for the third value by subtracting those two from 180.
180-89-4=87 degrees. Hope this helps!
Answer:
Answer. The circumference of the circle is 20π cm or about 62.8 cm.
Step-by-step explanation:
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Answer:
For maximum area of the rectangular exercise run dimensions will be 50ft by 25ft.
Step-by-step explanation:
Let the length of the rectangular exercise run = l ft
and width of the run = w ft
Sinoman has to cover a rectangular exercise run from three sides with the fencing material,
So length of the material = (l + 2w) ft
l + 2w = 100
l = 100 - 2w --------(1)
Area of the rectangular area covered = Length × width
A = lw
A = w(100 - 2w) [(l = 100 - 2w)from equation (1)
For maximum area we find the derivative of area and equate it to zero.
![\frac{dA}{dw}=\frac{d}{dw}[w(100-2w)]](https://tex.z-dn.net/?f=%5Cfrac%7BdA%7D%7Bdw%7D%3D%5Cfrac%7Bd%7D%7Bdw%7D%5Bw%28100-2w%29%5D)
A' = 100 - 4w
For A' = 0
100 - 4w = 0
4w = 100
w = 25 ft
From equation (1)
l = 100 - 2w
l = 100 - 2×(25)
l = 50 ft
Therefore, for maximum area of the rectangular exercise run dimensions will be 50ft by 25ft.
