Which number is a prime number?? 111 121 131 141

10 One of the legs of a right triangle has vertices with coordinates (-2,4) and (10,0).

jeka57 [31]

The equation of the line of the other leg of the right triangle if it shares the vertice of (10,0) is y = -1/3x + 10/3

<h3>How to find the equation of a line?</h3>

The equation of a line in slope-intercept form is expressed as y = mx + b

where

m is the slope

b is the y-intercept

Given the coordinate points (-2, 4) and (10, 0)

Find the slope

Slope = -4/12
Slope = -1/3

Determine the y-intecept

0 = -1/3(10) + b

b = 10/3

Determine the equation

y = -1/3x + 10/3

Hence the equation of the line of the other leg of the right triangle if it shares the vertice of (10,0) is y = -1/3x + 10/3

Learn more on equation of a line here: brainly.com/question/13763238

7 0

2 years ago

What is distributive property?

Svet_ta [14]

Answer:

To distribute means to divide something or give a share or part of something. For example, for the problem 4(6+2), you would use the distributive property and distribute the 4. Making the end result, 24+8.

5 0

2 years ago

X

erica [24]

Answer: 67.725feet²

Step-by-step explanation:

A heptagon consist of 7 sides and Its area is calculated using the formula

= 1/2 × nsr

n = number of sides = 7

s = side length = 4.3

r = apothem = 4.5

Area = 1/2 × nsr

= 1/2 × 7 × 4.3 × 4.5

= 0.5 × 7 × 4.3 × 4.5

= 67.725feet²

7 0

2 years ago

Find the absolute maximum and minimum values of f(x, y) = x+y+ p 1 − x 2 − y 2 on the quarter disc {(x, y) | x ≥ 0, y ≥ 0, x2 +

Andreas93 [3]

Answer:

absolute max: f(x,y)=1/2+p1 ; at P(1/2,1/2)

absolute min: f(x,y)=p1 ; at U(0,0), V(1,0) and W(0,1)

Step-by-step explanation:

In order to find the absolute max and min, we need to analyse the region inside the quarter disc and the region at the limit of the disc:

Region inside the quarter disc:

There could be Minimums and Maximums, if:

∇f(x,y)=(0,0) (gradient)

we develop:

(1-2x, 1-2y)=(0,0)

x=1/2

y=1/2

Critic point P(1/2,1/2) is inside the quarter disc.

f(P)=1/2+1/2+p1-1/4-1/4=1/2+p1

f(0,0)=p1

We see that:

f(P)>f(0,0), then P(1/2,1/2) is a maximum relative

Region at the limit of the disc:

We use the Method of Lagrange Multipliers, when we need to find a max o min from a f(x,y) subject to a constraint g(x,y); g(x,y)=K (constant). In our case the constraint are the curves of the quarter disc:

g1(x, y)=x^2+y^2=1

g2(x, y)=x=0

g3(x, y)=y=0

We can obtain the critical points (maximums and minimums) subject to the constraint by solving the system of equations:

∇f(x,y)=λ∇g(x,y) ; (gradient)

g(x,y)=K

Analyse in g2:

x=0;

1-2y=0;

y=1/2

Q(0,1/2) critical point

f(Q)=1/4+p1

We do the same reflexion as for P. Q is a maximum relative

Analyse in g3:

y=0;

1-2x=0;

x=1/2

R(1/2,0) critical point

f(R)=1/4+p1

We do the same reflexion as for P. R is a maximum relative

Analyse in g1:

(1-2x, 1-2y)=λ(2x,2y)

x^2+y^2=1

Developing:

x=1/(2λ+2)

y=1/(2λ+2)

x^2+y^2=1

So:

(1/(2λ+2))^2+(1/(2λ+2))^2=1

$\lambda_{1}=\sqrt{1/2}*-1 =-0.29$

$\lambda_{2}=-\sqrt{1/2}*-1 =-1.71$

$\lambda_{2}$ give us (x,y) values negatives, outside the region, so we do not take it in account

For $\lambda_{1}$ : S(x,y)=(0.70, 070)

and

f(S)=0.70+0.70+p1-0.70^2-0.70^2=0.42+p1

We do the same reflexion as for P. S is a maximum relative

Points limits between g1, g2 y g3

we need also to analyse the points limits between g1, g2 y g3, that means U(0,0), V(1,0), W(0,1)

f(U)=p1

f(V)=p1

f(W)=p1

We can see that this 3 points are minimums relatives.

Conclusion:

We compare all the critical points P,Q,R,S,T,U,V,W an their respective values f(x,y). We find that:

absolute max: f(x,y)=1/2+p1 ; at P(1/2,1/2)

absolute min: f(x,y)=p1 ; at U(0,0), V(1,0) and W(0,1)

4 0

3 years ago

Which statement is true?

Veronika [31]

Answer:

B. Only 140 is an outlier

Step-by-step explanation:

To properly identify an outlier, you must first know what it is. An outlier is a number that is either a lot higher or a lot lower than the average in a set of numbers. For example, if you had a number set of 1, 3, 4, 6, and 72, you can deduce that 72 is the outlier because it's very far away compared to the other numbers in the set.

In the set that's provided, the numbers tend to range in the double digits, going up in small increments from 15 to 89. However, we can see that 140 is a lot higher than the rest of the numbers in the set, so we can assume that 140 is an outlier.

7 0

3 years ago

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