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melomori [17]
1 year ago
15

Matthew plays basketball for his high school. On average, he scores 33 points per game, with a standard deviation of 2 points. W

hat percentage of basketball games will result in Matthew scoring less than 27 points?
Note: Assume that a Normal model is appropriate for the distribution of points.

Mathematics
2 answers:
Mars2501 [29]1 year ago
6 0

Answer:

I believe is the correct answer

Step-by-step explanation:

a

Lera25 [3.4K]1 year ago
3 0
<h3>Answer: Choice B</h3>

Matthew will score less than 27 points in about 0.15% of his basketball games.

=======================================================

Explanation:

mu = 33 = population mean

sigma = 2 = population standard deviation

Let's find the z score when x = 27

z = (x - mu)/sigma

z = (27-33)/2

z = -6/2

z = -3

A score of 27 points is exactly three standard deviation units below the mean of 33 points.

Now refer to the Empirical Rule chart shown below. Notice that roughly 99.7% of the entire population is within 3 standard deviations of the mean. This is the span from z = -3 to z = 3.

That leaves about 100% - 99.7% = 0.3% left over for the two tails combined.

One tail has about (0.3%)/2 = 0.15% of the total area, and therefor about 0.15% of the total games will have Matthew scoring less than 27 points. This is an estimate of course.

To get a more accurate answer, you can use a Z table to find that

P(Z < -3) \approx 0.00135 \approx 0.135\%

which isn't too far off from the 0.15%

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ser-zykov [4K]

Answer:

3/32

Step-by-step explanation:

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3 years ago
According to a survey, 18% of the car owners said that they get the maintenance service done on their cars according to the sche
Annette [7]

Answer:

a) For this case we define the random variable X="number of car owners in a random sample of 12 who get the maintenance service done on their cars according to the schedule recommended by the auto company". And for this case the distribution for X is:

X \sim Binom (n =12, p=0.18)

And the possible values for the random variable are X=0,1,2,3,4,5,6,7,8,9,10,11,12

b) Using the probability mass function we got:

P(X=3)=(12C3)(0.18)^3 (1-0.18)^{12-3}=0.21506

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

Solution to the problem

Part a

For this case we define the random variable X="number of car owners in a random sample of 12 who get the maintenance service done on their cars according to the schedule recommended by the auto company". And for this case the distribution for X is:

X \sim Binom (n =12, p=0.18)

And the possible values for the random variable are X=0,1,2,3,4,5,6,7,8,9,10,11,12

Part b

Find to 3 decimal places the probability that exactly 3 car owners in a random sample of 12 get the maintenance service done on their cars according to the schedule recommended by the auto company.

Using the probability mass function we got:

P(X=3)=(12C3)(0.18)^3 (1-0.18)^{12-3}=0.21506

6 0
2 years ago
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irga5000 [103]
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2 years ago
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Arte-miy333 [17]
Factors of 36 that differ by 9 are 12 and 3; 
<span>12*3 = 36 </span>
<span>Or you could write x(x - 9) - 36 = (x - 12)(x + 3) = 0 </span>
<span>The number was 12</span>
5 0
3 years ago
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