Answer:
4.9:13.1
Step-by-step explanation:
V=4/3*pi*r^3
Answer:
5ln3=ln(3^5)
Step-by-step explanation:
Given: 5ln(3)
Use rule: alog(b)=log(b^a), aln(b)=ln(b^a) (doesn't matter what the log base is)
Apply rule: ln(3^5)
So you will need to solve for x and y before evaluating 2x+y....
2x-y=9, y=2x-9 now this will make 4x^2-y^2=171 become:
4x^2-(2x-9)^2=171
4x^2-(4x^2-36x+81)=171
36x-81=171
36x=252
x=7, now we can use 2x-y=9 to solve for y...
2(7)-y=9
14-y=9
-y=-5
y=5
now we know that x=7 and y=5, 2x+y becomes:
2(7)+5
14+5
19
