Answer:
Neither binomial nor normal distribution
Step-by-step explanation:
In binomial distribution Sumner of trials are fixed and there is only two outcomes either success or failure
But in this question there are no fixed trials and outcomes is not proper so this is not a binomial distribution.
In normal distribution there is information of mean and variance which is also not give in the question so it is also nit a normal distribution
So it is neither binomial nor normal distribution
Answer:
<u>Volume</u>
For the rectangle, h = 3cm, l = 8cm, w = 6cm
V = length x width x height
V = 8cm x 6cm x 3cm
V = 144cm^3
For the semi circle, we need to find the radius. The radius is width/2, so 6cm/2 = 3cm. r = 3cm,
= 3.14
V = radius^2 x height x 
V = 3cm^2 x 3cm x 3.14
V = 84.8 cm^3/2 (because the cylinder needs to be divided to form a semi-circle)
V= 42.4cm^3 (there are two cylinders though so we will multiply this by 2 in the total volume)
Total volume:
V = 144cm^3 + 42.4cm^3(2)
V = 186.4cm^3
<u>Surface Area</u>
Rectangular prism:
A = 2[w(l) + h(l) + h(w)]
A = 2[6cm(8cm) + 3cm(8cm) + 3cm(6cm)]
A = 180cm^2
But there are two sides that are covered by the semi-circular prisms, so we will have to calculate those sides and remove them.
A = l x w
A = 6cm x 3cm
A = 18cm^2(2) (2 being the two faces)
A = 36cm^2
A = 180cm^2 - 36cm^2
A = 144cm^2 (the area of the rectangle)
Semi-circular prism:
A = 2
rh + 2
r^2
Earlier, we found out that the radius of the circle is 3cm, so we will plug that in.
A = 2(3.14)(3cm)(3cm) + 2(3.14)(3cm)^2
A = 113.09cm^2
Total surface area:
A = 144cm^2 + 133.09cm^2
A = 277.09cm^2
Therefore the total volume of the prism is 186.4cm^3 and the total surface area is 277.09cm^2.
1/4 of 20 is 5.. and 5/10, 3/6, 2/4, 6/12 are all equal to 1/2
Answer: No
Step-by-step explanation:-
Labeled diameter on the bolt = 0.35 inch
The observed diameter of the bolt= 0.33 inch


For the bolt to be in the package, the percent error must be less than 5%. As the percent error is 6.06% which is greater than 5%, the bolt cannot be in the package.
Volume: h • pi r^2
Volume: (7.5) • pi (2)^2
Volume: 94.247796
Just round to your teacher’s liking