1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
NeTakaya
2 years ago
6

What are the zeros of this function?

Mathematics
2 answers:
Rama09 [41]2 years ago
8 0

Answer:

A. x = 0 and x = 6

Step-by-step explanation:

So, the zeroes of a quadratic are the parts of it that touch the x-axis. When you find those parts, take their x value and you will get the zero.

So, in this parabola, it touches the x-axis at (0, 0) and (6, 0).

The x-values of these are 0 and 6, respectively.

Rzqust [24]2 years ago
3 0

Answer:

A

Step-by-step explanation:

The zeros are the roots or x-intercepts

They are located at coordinate points (0, 0) and (6, 0)

This means the answer is A

Hope it makes sense!

You might be interested in
5.08 in fraction form and simplest form with work!
TEA [102]
Are u in a middle of a test right now or something
3 0
3 years ago
Read 2 more answers
Which equation can be used to determine the distance between the origin and (–2, –4)?
Andreyy89
-2+(-4) i think :)))
3 0
2 years ago
Read 2 more answers
Order -1 2/3, 1- 3/8, -1 4/5, and -1 9/20
Elis [28]
From least to greatest?
5 0
3 years ago
Read 2 more answers
Simplify the expression by combining like terms:<br> 5c2 + 13c + 4 – 7c + 9
PIT_PIT [208]

Answer:

5c^2 +6c +13

Step-by-step explanation:

so we can see than 5c^2

and 13c - 7c are the same = 6c

and 4 +9 = 13

so answer will 5c^2 +6c +13

3 0
2 years ago
Read 2 more answers
Use the data in LAWSCH85 for this exercise. (i) Using the same model as in Problem 4 in Chapter 3, state and test the null hypot
natka813 [3]

Answer:

Step-by-step explanation:

In the model

Log (salary) = B0 + B1LSAT +B2GPA +B3log(libvol) +B4log(cost)+B5 rank+u

The hypothesis that rank has no effect on log (salary) is H0:B5 = 0. The estimated equation (now with standard errors) is

               Log (salary) =    8.34 +    .0047 LSAT +   .248 GPA +   .095 log(libvol)

                                        (0.53)     (.0040)              (.090)            (.033)

                                         +     .038 log(cost)    – .0033 rank

                                              (.032)                    (.0003)

                   n = 136,    R2 = .842.

The t statistic on rank is –11(i.e. 0.0033/0.0003), which is very significant. If rank decreases by 10 (which is a move up for a law school), median starting salary is predicted to increase by about 3.3%.

(ii) LSAT is not statistically significant (t statistic ≈1.18) but GPA is very significance (t statistic  ≈2.76). The test for joint significance is moot given that GPA is so significant, but for completeness the F statistic is about 9.95 (with 2 and 130 df) and p-value ≈.0001.

6 0
3 years ago
Other questions:
  • a motorcycle weighs about 250 pounds. a school bus weighs 25,000 pounds. how many times greater is the weight of a bus than the
    5·1 answer
  • Polygon ABCD will be dilated by a factor of 2 to produce polygon A′B′C′D′. The origin is the center of dilation. Which point wil
    7·1 answer
  • The sum of two numbers is 186.The difference between the same numbers is 32. What are the two numbers?
    8·1 answer
  • What is the equation process to this question?
    15·1 answer
  • Can someone hlpe with questions A and/or B please
    8·1 answer
  • Y=1.9x+2.5 what does this equal
    6·2 answers
  • There are 10 computers and 5 students. How many ways are there for the students to sit at the computers if no computer has more
    15·1 answer
  • ????????????????vbzjjzjdvdu
    5·2 answers
  • A radioactive substance decays at a rate of 25% every 10 years. Which equation represents the amount of the substance (S) remain
    5·1 answer
  • Find the area of the shaded region.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!