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3 years ago

Identify the location of the values used to create a box

Mathematics

2 answers:

mafiozo [28]3 years ago

6 0

Answer:

A= minimum value

B=lower quartile

C=median

D= upper quartile

E= maxuim value

Step-by-step explanation:

Dominik [7]3 years ago

4 0

Answer:A= minimum value

B=lower quartile

C=median

D= upper quartile

E= maxuim value

Step-by-step explanation:

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Which point is a reflection of T(-6.5, 1) across the x-axis and the y-axis?

drek231 [11]

First, start off with the x-axis. -6.5, 1 becomes 6.5, 1. This is because point T is 6.5 to the left of the x-axis line, so our new point would be 6.5 to the right of the x-axis line. Same thing for the y-axis, (6.5, 1) would become (6.5, -1).

8 0

3 years ago

If m ∠ 8 = 65 degrees, what is m ∠ 5 ? (Image in details)

Nitella [24]

65°

It's opposite on a 180° line.

7 0

3 years ago

To pay for new machinery in 5 years a company owner invests $10000 at 7.5% compounded quarterly. How much money will be availabl

sukhopar [10]

Answer:

37 500

Step-by-step explanation:

6 0

3 years ago

A student committee is to consist of 2 freshmen, 5 sophomores, 4 juniors, and 3 seniors. If 6 freshmen, 13 sophomores, 8 juniors

mezya [45]

<h3>Answer: 491,891,400</h3>

Delete the commas if necessary.

============================================================

Explanation:

There are 6 freshmen total and we want to pick 2 of them, where order doesn't matter. The reason it doesn't matter is because each seat on the committee is the same. No member outranks any other. If the positions were labeled "president", "vice president", "secretary", etc, then the order would matter.

Plug n = 6 and r = 2 into the nCr combination formula below

$n C r = \frac{n!}{r!(n-r)!}\\\\6 C 2 = \frac{6!}{2!*(6-2)!}\\\\6 C 2 = \frac{6!}{2!*4!}\\\\6 C 2 = \frac{6*5*4!}{2!*4!}\\\\ 6 C 2 = \frac{6*5}{2!}\\\\ 6 C 2 = \frac{6*5}{2*1}\\\\ 6 C 2 = \frac{30}{2}\\\\ 6 C 2 = 15\\\\$

This tells us there are 15 ways to pick the 2 freshmen from a pool of 6 total.

Repeat those steps for the other grade levels.

n = 13 sophomores, r = 5 selections leads to nCr = 13C5 = 1287. This is the number of ways to pick the sophomores.

You would follow the same type of steps shown above to get 1287. Let me know if you need to see these steps.

Similarly, 8C4 = 70 is the number of ways to pick the juniors.

Lastly, 14C3 = 364 is the number of ways to pick the seniors.

-----------------------------

To recap, we have...

15 ways to pick the freshmen
1287 ways to pick the sophomores
70 ways to pick the juniors
364 ways to pick the seniors

Multiply out those values to get to the final answer.

15*1287*70*364 = 491,891,400

This massive number is a little under 492 million.

7 0

2 years ago

Geometry question on finding x.

Dmitrij [34]

Answer:

$x =63^o$

Step-by-step explanation:

Given :-

$\text{ $\overline{MN} $ and $\overline{ML}$ are tangents .}$

We know that the tangents are perpendicular to the radius at the point of contact . And here OLMN is a quadrilateral. Also we know that , the angle sum property a triangle is 360° .

According to question :-

$\implies x + 117^o + 90^o +90^o = 360^o \\\\\implies x + 297^o = 360^o \\\\\implies x = 360^o - 297^o \\\\\implies x = 63^o$

Hence the value of x is 63° .

6 0

3 years ago