For 20% out of 100% it would be 1/5 as you need 5 20s for 100
Answer:
50%
Step-by-step explanation:
68-95-99.7 rule
68% of all values lie within the 1 standard deviation from mean 
95% of all values lie within the 1 standard deviation from mean 
99.7% of all values lie within the 1 standard deviation from mean 
The distribution of the number of daily requests is bell-shaped and has a mean of 55 and a standard deviation of 4.

68% of all values lie within the 1 standard deviation from mean
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95% of all values lie within the 2 standard deviation from mean
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99.7% of all values lie within the 3 standard deviation from mean
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Refer the attached figure
P(43<x<55)=2.5%+13.5%+34%=50%
Hence The approximate percentage of light bulb replacement requests numbering between 43 and 55 is 50%
Use the substitution method
V= s^3
2*2*2= 8 cm^ 3
Answer : 8 cm^ 3 - A
Answer:
(x,y) + (x-4, y)
Step-by-step explanation:
horizontally means it would be on the x axis traveling to the left would be your subtracting there fore the only answer which comes with a x-4 is (x,y) + (x-4, y)