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3 years ago

How do you do distributive property with mixed numbers ?

Mathematics

1 answer:

vichka [17]3 years ago

6 0

Ex: 3 4/5 = 3 x 5 + 4= 19/5

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Elodia [21]

Answer:

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Step-by-step explanation:

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2 years ago

Given: △ACE, BD∥AE<br><br> Prove: BA/CB=DE/CD<br><br> Drag

gizmo_the_mogwai [7]

Answer:

Step-by-step explanation:

Angle 4 = angle 1 and angle 3 =angle 2 Corresponding angles for two parallel lines BD and AE

Triangle AED ||| BDE Angle angle congruent

... By compendo and dividendo

Thus proved

Since two lines are parallel we have corresponding angles equal and also

sides will be proportional in similar triangles

Using that and adjusting compendo and dividendo we get the desired result

6 0

3 years ago

Read 2 more answers

The length of a rectangle is 8cm and the height is 16cm find the answer of the above figures using this formular...

notsponge [240]

Length=8cm
Breadth=16cm(Height)

<h3>Perimeter:-</h3>

$\\ \sf\longmapsto Perimeter=2(L+B)$

$\\ \sf\longmapsto Perimeter=2(16+8)$

$\\ \sf\longmapsto Perimeter=2(24)$

$\\ \sf\longmapsto Perimeter=48cm$

Area:-

$\\ \sf\longmapsto Area=Length\times Breadth$

$\\ \sf\longmapsto Area=8(16)$

$\\ \sf\longmapsto Area=128cm^2$

3 0

3 years ago

Evaluate f(x) = 8.4x + 3.8 when x = 9.1. Type the number only for auto grade to work correctly. Round your answer to 2 decimal p

vova2212 [387]

The answer is 80.24.

3 0

3 years ago

What are the amplitude, period, and phase shift of the given function? f(t)=-1/2sin(3t-2pi)

Romashka [77]

Answer:

The $amplitude=|A|=\frac{1}{2}$ , $period=3$ and $\text{phase shift}=\frac{2\pi}{3}$ .

Step-by-step explanation:

The given function is

$f(t)=-\frac{1}{2}\sin (3t-2\pi)$ .... (1)

The general form of sine function is

$F(t)=A\sin (Bt-C)+D$ ....(2)

where, |A| is the amplitude, B is period, D is the vertical shift (up or down), and C/B is used to find the phase shift.

On comparing (1) and (2), we get

$A=-\frac{1}{2}$

$B=3$

$C=2\pi$

$D=0$

So,

$amplitude=|A|=\frac{1}{2}$

$period=3$

$\text{phase shift}=\frac{2\pi}{3}$

Therefore $amplitude=|A|=\frac{1}{2}$ , $period=3$ and $\text{phase shift}=\frac{2\pi}{3}$ .

8 0

3 years ago