3 years ago

4k+2/k2-4 • k-2/2k+1= What is the numerator ?

Mathematics

1 answer:

eduard3 years ago

8 0

(4k+2)(k-2)/(k^2-4)(2k+1)

=2(2k+1)(k-2)/ (k^2-2^2)(2k+1)

Cancel out 2k+1

2(k-2)/(k-2)(k+2) using a^2-b^2=(a-b)(a+b)

cancel out k-2

2/k+2

Therefore numerator is 2

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alexgriva [62]

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You could've got this by multiplying -5 and x together, which is -5x.
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