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Tanya [424]
3 years ago
15

15 People fit comfortably in a 6 feet by 6 feet area. Use this value to estimate the size of a crowd that is 7 feet deep on both

sides of the street along a 2-mile section of a parade route.
Mathematics
1 answer:
dexar [7]3 years ago
7 0

Answer:

\boxed{\text{30 800 people}}

Step-by-step explanation:

1. Area of the crowd

The crowd fills a rectangle that is 2 mi long and 7 ft wide.

(a) Convert miles to feet.

\text{l} = \text{2 mi} \times \dfrac{\text{5280 ft}}{\text{1 mi}} = \text{10 560 ft}

(b) Calculate the area

A  = lw = 10 560 ft × 7 ft = 73 920 ft²

2. Size of crowd

15 people occupy an area of 6 ft × 6 ft = 36 ft²

\text{Size of crowd} = \text{73 920 ft}^{2}\times \dfrac{\text{15 people}}{\text{36 ft}^{2}} = \textbf{30 800 people}\\\text{The size of the crowd is $\boxed{\textbf{30 800 people}}$}

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<h3>What are Simultaneous equations?</h3>

Simultaneous equations are two or more algebraic equations with the same unknown variables and the same value of the variables satisfies all such equations.

We can solve simultaneous equations by various methods. here we will solve it by elimination method.

Here we have two simultaneous equations

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<u>NOTE</u> : The question given here is not complete. The complete question is given below.

Question: What is the solution of the simultaneous equations 3x- 2y= 14 and 4x+ 3y= 13?.

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