Answer:
y-3 = 4(x+2) point slope form
y = 4x+11 slope intercept form
Step-by-step explanation:
Since we have a point and a slope, we will start with point slope form
y-y1 = m(x-x1)
y-3 = 4(x--2)
y-3 = 4(x+2)
This is point slope form
Distribute
y-3 = 4x+8
Add 3 to each side
y-3+3 = 4x+8+3
y = 4x+11
slope intercept form
Answer:
A
Step-by-step explanation:
y - 3 = 5(x - 2)
y - 3 = 5x - 10 Add 3 to both sides
y = 5x - 7
Let x = 2
y = 5*2 - 7
y = 3
So (2,3) works
Let x = 3
y = 5*3 - 7
y = 15 -7
y = 8
The answer is A
Answer:
The line you're looking for is parallel to y = 3x – 9, so it also has a slope of 3. Thus, you can rule out ... Here's what your work should look like: y = mx + b 0 = 3(–3) + b 0 = –9 + b 9 = b Now that you know both the slope and the y-intercept for this line, you can write the equation in the slope-intercept form: y = mx + b y = 3x + 9 The correct answer is Choice (C). What is the equation of a line that passes through the point (0, 3) and is perpendicular to y = 8x + 5? (F) y = 8x (G) y = 8x + 3 (H) (J)
Step-by-step explanation:
Answer:
It's C
The X and Y coordinates are both negative
Step-by-step explanation:
Quadrant 1- negative and positive
Quadrant 2- positive and positive
Quadrant 3- negative and negative
Quadrant 4-positive and negative
