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alekssr [168]
2 years ago
7

What is the domain of F(x)=9-x?? F F(x) >9 G All real numbers H-3 1 x59

Mathematics
1 answer:
Julli [10]2 years ago
8 0
I’m pretty sure it’s h because the lines meet in the x axis
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Which of the following represents the general term for the sequence 1, 3, 5, 7, 9, . . .? n
zalisa [80]

Answer:

Step-by-step explanation:

In the given sequence, the terms are increasing in arithmetic progression. The common difference, d between successive terms is 2

The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + (n - 1)d

Where

a represents the first term of the sequence.

d represents the common difference.

n represents the number of terms in the sequence.

From the information given,

a = 1

d = 2

Therefore, the expression for the general term for the sequence is

Tn = 1 + 2(n - 1)

3 0
3 years ago
need a lot of help
marishachu [46]
2.60 x 12 3/4

2.60 x 12.75 (convert to decimal)

= $33.15, which is not listed.
3 0
2 years ago
The total for shipping charges for the 8 full boxes was $54.75 more than the total for shipping charges for the partially filled
lakkis [162]

Answer:

Step-by-step explanation:

536 because it is correct

4 0
3 years ago
What is the volume in the tank after two hours of the pumps running v(t)= 65t + 280
alina1380 [7]

Answer:

imma look this up rq

Step-by-step explanation:

4 0
3 years ago
Justin is constructing a line through point Q that is perpendicular to line n. He has already constructed the arcs shown. He pla
krek1111 [17]
<span>B. It must be the same as when he constructed the arc centered at point A. This problem would be a lot easier if you had actually supplied the diagram with the "arcs shown". But thankfully, with a few assumptions, the solution can be determined. Usually when constructing a perpendicular to a line through a specified point, you first use a compass centered on the point to strike a couple of arcs on the line on both sides of the point, so that you define two points that are equal distance from the desired intersection point for the perpendicular. Then you increase the radius of the compass and using that setting, construct an arc above the line passing through the area that the perpendicular will go. And you repeat that using the same compass settings on the second arc constructed. This will define a point such that you'll create two right triangles that are reflections of each other. With that in mind, let's look closely at your problem to deduce the information that's missing. "... places his compass on point B ..." Since he's not placing the compass on point Q, that would imply that the two points on the line have already been constructed and that point B is one of those 2 points. So let's look at the available choices and see what makes sense. A .It must be wider than when he constructed the arc centered at point A. Not good. Since this implies that the arc centered on point A has been constructed, then it's a safe assumption that points A and B are the two points defined by the initial pair of arcs constructed that intersect the line and are centered around point Q. If that's the case, then the arc centered around point B must match exactly the setting used for the arc centered on point A. So this is the wrong answer. B It must be the same as when he constructed the arc centered at point A. Perfect! Look at the description of creating a perpendicular at the top of this answer. This is the correct answer. C. It must be equal to BQ. Nope. If this were the case, the newly created arc would simply pass through point Q and never intersect the arc centered on point A. So it's wrong. D.It must be equal to AB. Sorta. The setting here would work IF that's also the setting used for the arc centered on A. But that's not guaranteed in the description above and as such, this is wrong.</span>
8 0
3 years ago
Read 2 more answers
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