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3 years ago

Simplify the expression. The expression is (5x+1/2)+(9x-2 1/2)

Mathematics

1 answer:

Alexxandr [17]3 years ago

5 0

All you have to do here is combine like terms.
5x + 9x = 14x
.5 - 2.5 = -2

14x - 2

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ratelena [41]

Answer:

Sorry

Step-by-step explanation:

Sorry i need the points.

3 0

3 years ago

Simplify 81.56 + n - 2.55. 79.10 - n 79.01 + n 81.56 - 2.55n

vitfil [10]

Answer:

79.01 + n

Step-by-step explanation:

81.56 + n - 2.55

Put like terms together.

81.56 - 2.55 + n

Solve.

81.56- 2.55

= 79.01

Add all values together and add n in the end.

79.01 + n

Therefore the answer is 79.01 + n

4 0

3 years ago

HELP

andreev551 [17]

Answer:

A. y = 80x

B. g(x) = 80x

C. To graph the equation, plot a point at (0,0) and a point at (1,80). Connect the points. Continue adding points by moving up $80 and over 1 day.

Step-by-step explanation:

Part A:

To write an equation, use y= mx where m is the slope, x is the number of days, and y is the rent cost.

x and y remain the same in the equation.

To find m, use the slope formula with (5,465) and (7, 625).

$m=\frac{y_2-y_1}{x_2-x_1}= \frac{625-465}{7-5} =\frac{160}{2} =80$

It costs $80 a day.

The equation is y = 80x.

Part B:

Function notation replaces Y as g(x). So the equation is g(x) = 80x.

Part C:

To graph the equation, plot a point at (0,0) and a point at (1,80). Connect the points. Continue adding points by moving up $80 and over 1 day.

6 0

3 years ago

Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the

Rama09 [41]

Question:

Britney throws an object straight up into the air with an initial velocity of 27 ft/s from a platform that is 10 ft above the ground. Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the object to hit the ground?

1s 2s 3s 4s

Answer:

It takes 2 seconds for object to hit the ground

Solution:

The given equation is:

$h(t) = -16t^2 + v_0t+h_0$

Initial velocity = 27 feet/sec

$h_0 = 10\ feet$

Therefore,

$h(t) = -16t^2 +27t+10$

At the point the object hits the ground, h(t) = 0

$-16t^2 +27t+10 = 0\\\\16t^2-27t-10=0$

Solve by quadratic formula,

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=16,\:b=-27,\:c=-10:\quad \\\\t=\frac{-\left(-27\right)\pm \sqrt{\left(-27\right)^2-4\cdot \:16\left(-10\right)}}{2\cdot \:16}\\\\t = \frac{27 \pm \sqrt{1369}}{32}\\\\t = \frac{27 \pm 37}{32}\\\\We\ have\ two\ solutions\\\\t = \frac{27+37}{32}\\\\t = \frac{64}{32}\\\\t = 2\\\\And\\\\t = \frac{27-37}{32}\\\\t = -0.3125$

Ignore, negative value

Thus, it takes 2 seconds for object to hit the ground

7 0

3 years ago

PLEASE HELP ASAP

Dafna1 [17]

Answer:

Step-by-step explanation:

27.068

28.08

28.15

29.94

6 0

2 years ago

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