Answer:
Step-by-step explanation:
Because the trapezoid is isosceles, the two diagonals are congruent. This can be shown by ASA.
ACD = BDC Properties of parallel lines.
DC = DC A line is equal to itself
DBA = CAB Property of parallel lines.
AC = DB Parts of Congruent triangles are congruent
3x + 15 = 7x - 9 Add 9 to both sides
3x + 15 + 9 = 7x
3x + 24 = 7x Subtract 3x from both sides.
24 = 7x - 3x
24 = 4x Divide by 4
24/4 = 4x/4
x = 6
Answer:
1. Yes
∆RST ~ ∆WSX
by SAS
2. Yes
∆ABC ~ ∆PQR
by SSS
3. Yes
∆STU ~ ∆JPM
by SAS
4. Yes
∆DJK ~ ∆PZR
by SAS
5. Yes
∆RTU ~ ∆STL
by SAS
5. Yes
∆JKL ~ ∆XYW
by SAS
6. No
7. Yes
∆BEF ~ ∆NML
by SAS
8. Yes
∆GHI ~ ∆QRS
by SSS
9. x=22
10. x=12
Step-by-step explanation:
1. RS/WS=ST/SX and m<RST=m<WSX
2. AB/PQ=8/6=4/3
BC/QR=AC/PR=12/9=4/3
AB/PQ=BC/QR=AC/PR
3. ST/JP=10/15=2/3
SU/JM=14/21=2/3
ST/JP=2/3=SU/JM
and m<TSU=70°=m<PJM
4. DK/PR=8/4=2
JK/ZR=18/9=2
DK/PR=2=JK/ZR
and m<DKJ=65°=m<PRZ
5. RT/ST=UT/LT
and m<RTU=m<STL
6. KL/YW=20/18=10/9
JL/XW=36/24=3/2
KL/YW=10/9≠3/2=JL/XW
7. BF/NL=24/16=3/2
BE/NM=39/26=3/2
BF/NL=3/2=BE/NM
and m<EBF=m<MNL
8. GH/QR=32/20=8/5
HI/RS=40/25=8/5
GI/QS=24/15=8/5
GH/QR=HI/RS=GI/QS=8/5
9. x/33=18/27
Simplifying the fraction on the right side of the equation:
x/33=2/3
Solving for x: Multiplying both sides of the equation by 33:
33(x/33)=33(2/3)
x=11(2)
x=22
10. x/16=9/12
Simplifying the fraction on the right side of the equation:
x/16=3/4
Solving for x: Multiplying both sides of the equation by 16:
16(x/16)=16(3/4)
x=4(3)
x=12
Answer:
pounds
Step-by-step explanation:
The customer will be charged extra if the weight of their suitcase is above 48 pounds.
Let the weight of the suitcase = w (in pounds)
Therefore, w above (greater than) 48 pounds is written mathematically as:
pounds
This is the inequality that represents w, the weight of the suitcase in pounds, that will have an extra charge.
Answer:
120 sq ft.
Step-by-step explanation:
REMEMBER: Area is found by multiplying one side, by the other side that isn't the same length as it.
Multiply 12 by 10 to get 120
120 is the area of the bedroom
Responder:
26,62
Explicación paso a paso:
Sea x el dinero original que tenía el jugador:
si un jugador pierde en su primer juego el 30% de su dinero, la cantidad perdida será;
Si en el segundo juego pierde el 50% de lo que perdió, entonces la cantidad perdida en el segundo juego será:
Si en el tercer juego pierde el 40% de todo lo que ha perdido, la cantidad perdida en el tercer juego será:
Si la cantidad que le queda para seguir apostando es de 37 soles, entonces para calcular la cantidad original que tiene, sumaremos toda la cantidad perdida y la cantidad restante y equipararemos la cantidad original x como se muestra:
0,3x + 0,15x + 0,2025x + 37 = x
0,6525x + 37 = x
x-0,6525x = 37
0,3475x = 37
x = 37 / 0,3475
x = 106,48
La cantidad que tenía originalmente era de 106,48
75% de 106,48
= 75/100 * 106,48
= 0,75 * 106,48
= 79,86
Tomando la diferencia entre su monto original y su 75% será:
