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AleksAgata [21]
3 years ago
5

PLSSS HELP ME CORRECT ANSWER GETS BRAINLIEST

Mathematics
1 answer:
Alexxandr [17]3 years ago
7 0

Answer:

A is True

B is False

C is False

D is False

E is True

Lastly, F is False

Step-by-step explanation:

A would be= 71+27+50+50+50+48+48+47+47+45=518. Then you divide that by ten and you get 51.8

The mode is the most often reoccurring number We have 50 three times but 48 only twice.

The median is when you line all the numbers up in order and cross them out. It would look like this 71,57,50,50,50,48,48,47,47,45 however when y=we we cross the out we get both 50 and 48 in the middle when that happens we add them together and divide by two. That would get us 50+48=98/2=49 not 48

There are only two animals that can go faster than 50 mph ( The cheetah goes 57 mph and the Pronghorn antelope goes 57)

There are 7 animals faster than 47 mph so 7/10 as a percentage is 70%

The lowest and highest speed are 71 and 45 if we take those out we are left with 57+50+50+50+48+48+47+47 And that equals 49.625 which is lower than our old mean of 51.8

I hope this helps, have an amazing day!

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Step-by-step explanation:

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10^log23 =?
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3 years ago
Ana bikes for 5.5 hours. She covers a distance of 57.75 mi. Assuming she bikes at a constant speed, how fast was Ana biking?
Doss [256]
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hope this helps :)
3 0
3 years ago
Read 2 more answers
Multiply
Dmitriy789 [7]

Answer:

The product of given two fractions is

\frac{4(x+2)}{(x-1)(x+3)}

Therefore \frac{2(2+3)}{x(x-1)}\times \frac{4x(x+2)}{10(x+3)}=\frac{4(x+2)}{(x-1)(x+3)}

Step-by-step explanation:

Given expression is  

\frac{2(2+3)}{x(x-1)}\times \frac{4x(x+2)}{10(x+3)}

To find the product of two given fractions as below :

\frac{2(2+3)}{x(x-1)}\times \frac{4x(x+2)}{10(x+3)}=\frac{2(5)}{x(x-1)}\times \frac{2x(x+2)}{5(x+3)}

=\frac{10}{x(x-1)}\times \frac{2x(x+2)}{5(x+3)}

=\frac{20x(x+2)}{5x(x-1)(x+3)}

=\frac{20x^2+40x}{(5x^2-5x)(x+3)} (multiply each term in the factor to each term in the another factor )

=\frac{20x^2+40x}{5x^3+15x^2-5x^2-15x}  ( adding the like terms )

=\frac{20x^2+40x}{5x^3+10x^2-15x}

=\frac{5x(4x+8)}{5x(x^2+2x-3)}

=\frac{4(x+2)}{(x-1)(x+3)}

Therefore \frac{2(2+3)}{x(x-1)}\times \frac{4x(x+2)}{10(x+3)}=\frac{4(x+2)}{(x-1)(x+3)}

Therefore the product of given two fractions is \frac{4(x+2)}{(x-1)(x+3)}

6 0
3 years ago
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