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blsea [12.9K]
3 years ago
6

Find the volume of a right circular cone that has a height of 9.5 in and a base with a circumference of 3.4 in. Round your answe

r to the nearest tenth of a cubic inch.
Mathematics
1 answer:
Gekata [30.6K]3 years ago
8 0

Answer: 2.9 is the answer.

Step-by-step explanation:

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I NEED YOUR HELP!!<br> What is 2 + 3x8
Gemiola [76]

Answer:

Don't need Help don't depend on others do you'r work by yourself why you came to this world for asking help from other not do your work by yourself.Today I am going to help but from tomorrow you have to do by yourself

Step-by-step explanation:

=2x+3x8

=add

=5x8

=x=5=8/2

=x=5/4 is your answer

4 0
3 years ago
Read 2 more answers
Create a number line
wel

Step-by-step explanation:

is it correct ?? think that d answer is helpful to u

4 0
3 years ago
An equivalent expression for 4(x+2)+5(y+3)
Anit [1.1K]

Answer:

4x+5y+23

Step-by-step explanation:

4(x+2)+5(y+3)

4x+8+5y+15

4x+5y+8+15

4x+5y+23

7 0
3 years ago
wo point charges lie on the $x$ axis. A charge of +6.24 $\mu C$ is at the origin, and a charge of -9.55 $\mu C$ is at $x$ = 12.0
Andreyy89

Answer:

E_n=34,467,075.42\ N/C

Step-by-step explanation:

<u>Electric Field</u>

The electric field produced by a point charge Q at a distance d is given by

\displaystyle E=K\cdot \frac{Q}{d^2}

Where

K = 9\cdot 10^9\ Nw.m^2/c^2

The net electric field is the vector addition of the individual electric fields produced by each charge. The direction is given by the rule: If the charge is positive, the electric field points outward, if negative, it points inward.

Let's calculate the electric fields of each charge at the given point. The first charge q_1=+6.24\mu C=6.24\cdot 10^{-6}C is at the origin. We'll calculate its electric field at the point x=-3.85 cm. The distance between the charge and the point is d=3.85 cm = 0.0385 m, and the electric field points to the left:

\displaystyle E_1=9\cdot 10^9\cdot \frac{6.24\cdot 10^{-6}}{0.0385^2}

E_1=37,888,345.42\ N/C

Similarly, for q_2=-9.55\mu C=-9.55\cdot 10^{-6}C, the distance to the point is 12 cm + 3.85 cm = 15.85 cm = 0.1585 m. The electric field points to the right:

\displaystyle E_2=9\cdot 10^9\cdot \frac{9.55\cdot 10^{-6}}{0.1585^2}

E_2=3,421,270\ N/C

Since E1 and E2 are opposite, the net field is the subtraction of both

E_n=37,888,345.42\ N/C-3,421,270\ N/C

\boxed{E_n=34,467,075.42\ N/C}

6 0
3 years ago
How do I put (1352)⋅(1251)=1562652=117 into a fraction?
Dominik [7]

Answer:1.625=158

Step-by-step explanation:

Answer:

1.625=158

Showing the work

Rewrite the decimal number as a fraction with 1 in the denominator

1.625=1.6251

Multiply to remove 3 decimal places. Here, you multiply top and bottom by 103 = 1000

1.6251×10001000=16251000

Find the Greatest Common Factor (GCF) of 1625 and 1000, if it exists, and reduce the fraction by dividing both numerator and denominator by GCF = 125,

1625÷1251000÷125=138

Simplify the improper fraction,

=158

In conclusion,

1.625=158

6 0
2 years ago
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