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liraira [26]
3 years ago
11

PLEASE HELP ME!?!?! The equation of a standard pitcher’s mound in baseball is (x+5)^2 + (y+7)^2=81 The center the pitcher’s moun

d is ( , ).
Mathematics
1 answer:
lana [24]3 years ago
4 0

The equation (x+5)^2 + (y+7)^2=81 is a variation of a circles standard formula (x - h)^2 + (y - k)^2 = r^2

The center of the circle is found by (h, k)

In this case:

h = -5

k = -7

Therefore the center is:

(-5, -7)

Hope this helped!

~Just a girl in love with Shawn Mendes

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What is the next number in sequence 7, 2 , 0, 7, 8 , 4 , 3, ?
Taya2010 [7]
To solve for the next number, we need to assign a variable for the unknown number and let that be equal to X.
Then we have the solution below:
7+2+0+7=16
2+0+7+8=17 where 17=16+1
0+7+8+4=19 where 19=17+2
7+8+4+3=22 where 22=19+3
8+4+3+x=26 where 26=22+4
Therefore, the value of x is 11.
5 0
3 years ago
For the sequence -28,-16,-4,8,... The expression that defines the nth term where a 1 =-28 is 12 - 28n 2 12 - 28(n - 1) 3. - 28 +
GrogVix [38]

Answer:

a₁ = -28

aₙ = a₁ + 12 (n-1)

Step-by-step explanation:

a₁ = -28

a₂ = -28 + 12 (2 - 1) = -16

a₃ = -28 + 12 (3 - 1) = -4

a₄ = -28 + 12 (4 - 1) = 8

aₙ = a₁ + 12 (n-1)

7 0
3 years ago
Solve for x: one over eight 1/8(8x + 15) = 24
IgorC [24]

Answer:

22\frac{1}{8}

Step-by-step explanation:

I hope this helps!!!

5 0
2 years ago
Find the values of 121/101​
Leona [35]

The quotient of 121 and 101; when solved is; 1.198

<h3>Quotient of numbers</h3>

The given expression to be evaluated is;

  • 121/101

By observation, the numerator and denominator have no common factors and hence have time divided by means of a calculator or long division so that we have;

  • 121/101 = 1.1980198

  • = 1.198

Read more on quotients;

brainly.com/question/11418015

7 0
3 years ago
Read 2 more answers
Function f is represented by the equation shown.
aliya0001 [1]

Answer:

\boxed{\text{A.  The y-intercept of function f is greater than the y-intercept of function g}}

Step-by-step explanation:

A. y-Intercept of ƒ(x)

ƒ(x) = x² - 4x + 3

f(0) = 0² - 4(0) + 3 = 0 – 0 + 3 = 3

The y-intercept of ƒ(x) is (0, 3).

If g(x) opens downwards and has a maximum at y = 3, it's y-intercept is less than (0, 3).

Statement A is TRUE.

B. y-Intercept of g(x)

Statement B is FALSE.

C. Minimum of ƒ(x)

ƒ(x) = x² - 4x + 3

a = 1; b = -4; c = 3

The vertex form of a parabola is

y = a(x - h)² + k

where (h, k) is the vertex of the parabola.

h = -b/(2a) and k = f(h)

h = -b/2a = -(-4)/(2×1 = 2

k = f(2) = 2² - 4×2 + 3 =4 – 8 +3 = -1

The minimum of ƒ(x) is -1. The minimum of ƒ(x) is at (2, -1).

Statement C is FALSE.

D. Minimum of g(x)

g(x) is a downward-opening parabola. It has no minimum.

Statement D is FALSE

4 0
4 years ago
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