To solve for the next number, we need to assign a variable for the unknown number and let that be equal to X.
Then we have the solution below:
7+2+0+7=16
2+0+7+8=17 where 17=16+1
0+7+8+4=19 where 19=17+2
7+8+4+3=22 where 22=19+3
8+4+3+x=26 where 26=22+4
Therefore, the value of x is 11.
Answer:
a₁ = -28
aₙ = a₁ + 12 (n-1)
Step-by-step explanation:
a₁ = -28
a₂ = -28 + 12 (2 - 1) = -16
a₃ = -28 + 12 (3 - 1) = -4
a₄ = -28 + 12 (4 - 1) = 8
aₙ = a₁ + 12 (n-1)
Answer:
22
Step-by-step explanation:
I hope this helps!!!
The quotient of 121 and 101; when solved is; 1.198
<h3>Quotient of numbers</h3>
The given expression to be evaluated is;
By observation, the numerator and denominator have no common factors and hence have time divided by means of a calculator or long division so that we have;
Read more on quotients;
brainly.com/question/11418015
Answer:

Step-by-step explanation:
A. y-Intercept of ƒ(x)
ƒ(x) = x² - 4x + 3
f(0) = 0² - 4(0) + 3 = 0 – 0 + 3 = 3
The y-intercept of ƒ(x) is (0, 3).
If g(x) opens downwards and has a maximum at y = 3, it's y-intercept is less than (0, 3).
Statement A is TRUE.
B. y-Intercept of g(x)
Statement B is FALSE.
C. Minimum of ƒ(x)
ƒ(x) = x² - 4x + 3
a = 1; b = -4; c = 3
The vertex form of a parabola is
y = a(x - h)² + k
where (h, k) is the vertex of the parabola.
h = -b/(2a) and k = f(h)
h = -b/2a = -(-4)/(2×1 = 2
k = f(2) = 2² - 4×2 + 3 =4 – 8 +3 = -1
The minimum of ƒ(x) is -1. The minimum of ƒ(x) is at (2, -1).
Statement C is FALSE.
D. Minimum of g(x)
g(x) is a downward-opening parabola. It has no minimum.
Statement D is FALSE