We factor the denominators
Factor x^2 - 16
x^2 - 4^2
We use a^2 - b^2 = (a+b)(a-b)
so x^2 - 4^2 = (x+4)(x-4)
Replace it in the given equation
Excluded values are the values that makes the denominator 0
we have (x-4) and (x+4) in the denominator
We set the denominator =0 and solve for x
x-4 =0
Add 4 on both sides
x= 4
x+4=0
subtract 4 onboth side
so x= -4
Excluded values are x=-4 and x=4
8+11 is 19
Hope it helped
Answer:
Y=X/3+3
Step-by-step explanation:
M= Y2-Y1/X2-X1
= 5-6/6-9
= -1/-3
= 1/3
sub x=6, y=5, M=1/3 into Y=MX+C
5=6/3+C
5=2+C
5-2= 2+C-2
3=C
Answer:
(3, 0) and (5, 0)
Step-by-step explanation:
we have
we know that
The x-intercepts are the values of x when the value of y is equal to zero
so
For y=0
The formula to solve a quadratic equation of the form
is equal to
in this problem we have
so
substitute in the formula
so
x=3, x=5
therefore
The x-intercepts are (3,0) and (5,0)
