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olasank [31]
3 years ago
10

Molly can drive her car 112 miles on 4 gallons of gas and 182 miles on 6.5 gallons write an equation to show the relationship be

tween the number of gallons she has and the number of miles she can drive and how many gallons she would need to drive 420 miles
Mathematics
1 answer:
Rashid [163]3 years ago
3 0

Answer:

Molly can drive her car 112 miles on 4 gallons of gas and 182 miles on 6.5 gallons write an equation to show the relationship between the number of gallons she has and the number of miles she can drive and how many gallons she would need to drive 420 miles⊂⇄∪↓Ф

Step-by-step explanation:

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3 regions are defined in the figure find the volume generated by rotating the given region about the specific line
anastassius [24]

The volume generated by rotating the given region R_{3} about OC is \frac{4}{g}  \pi

<h3>Washer method</h3>

Because the given region (R_{3}) has a look like a washer, we will apply the washer method to find the volume generated by rotating the given region about the specific line.

solution

We first find the value of x and y

y=2(x)^{\frac{1}{4} }

x=(\frac{y}{2} )^{4}

y=2x

x=\frac{y}{2}

\int\limits^a_b {\pi } \, (R_{o^{2} }  - R_{i^{2} } )       dy

R_{o} = x = \frac{y}{2}

R_{i} = x= (\frac{y}{2}) ^{4}

a=0, b=2

v= \int\limits^2_o {\pi } \, [(\frac{y}{2})^{2} - ((\frac{y}{2}) ^{4} )^{2} )  dy

v= \pi \int\limits^2_o= [\frac{y^{2} }{4} - \frac{y^{8} }{2^{8} }}  ] dy

v= \pi [\int\limits^2_o {\frac{y^{2} }{4} } \, dy - \int\limits^2_o {\frac{y}{2^{8} } ^{8} } \, dy ]

v=\pi [\frac{1}{4} \frac{y^{3} }{3}  \int\limits^2_0 - \frac{1}{2^{8} }  \frac{y^{g} }{g} \int\limits^2_o\\v= \pi [\frac{1}{12} (2^{3} -0)-\frac{1}{2^{8}*9 } (2^{g} -0)]\\v= \pi [\frac{2}{3} -\frac{2}{g} ]\\v= \frac{4}{g} \pi

A similar question about finding the volume generated by a given region is answered here: brainly.com/question/3455095

6 0
2 years ago
HELP MEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE
goldfiish [28.3K]
Setup is
y = k/x
8 = k/3
k = 24

Now use 6 for y
6 = 24/x
x = 24/6 = 4 or A
5 0
3 years ago
Factor the quadratic expression in the equation y=2x^2+28x+96 and use the factors to find the zeros of the equation. Then, use t
gavmur [86]

Answer:

x=-7

Step-by-step explanation:

We have been given an equation y=2x^2+28x+96. We are asked to find the zeros of equation by factoring and then find the line of symmetry of the parabola.

Let us factor our given equation as:

2x^2+28x+96=0

Dividing both sides by 2:

x^2+14x+48=0

Splitting the middle term:

x^2+6x+8x+48=0

(x^2+6x)+(8x+48)=0

x(x+6)+8(x+6)=0

(x+8)(x+6)=0

Using zero product property:

(x+8)=0\text{ (or) }(x+6)=0

x+8=0\text{ (or) }x+6=0

x=-8\text{ (or) }x=-6

Therefore, the zeros of the given equation are x=-8\text{ (or) }x=-6.

We know that the line of symmetry of a parabola is equal to the x-coordinate of vertex of parabola.

We also know that x-coordinate of vertex of parabola is equal to the average of zeros. So x-coordinate of vertex of parabola would be:

\frac{-8+(-6)}{2}=\frac{-14}{2}=-7

Therefore, the equation x=-7 represents the line of symmetry of the given parabola.

4 0
3 years ago
Graph the system of linear inequalities, please explain the process in solving this problem so I know how to do ones similar to
astra-53 [7]

Answer:

See attached. (Both inequalities graph to the same region.)

Step-by-step explanation:

To graph an inequality, you first replace the inequality symbol by an equal sign. Then you graph the line (or curve) described by the equation. If the inequality symbol includes the "or equal to" case, then the line (or curve) is solid and is part of the solution set. If not, then the line (or curve) is dashed and is <em>not part of the solution set</em>.

Here, the line x+y=5, will bound the solution set, but is not part of it.

Note that the line -x -y = -5 (from the second inequality) is the same ilne.

_____

After you have graphed the boundary of the solution region, you need to determine which side of the boundary has the solutions. I find it easy to do this by locating an x- or y-term with a positive coefficient and seeing which side of the inequality symbol that lies on. Here, both the x-term and the y-term lie on the "is greater than" side of the symbol, so the half-plane is shaded above and to the right of the line, where x- and y-values are greater than they are on the line.

In the second inequality, you can multiply the whole thing by -1 to get

... x + y > 5 . . . . same as the first inequality

or you can add (x+y) to both sides to get

... 0 < -5 +x +y

Once again, the x- and y-values that satisfy this are greater than those that are on the boundary line.

_____

The graph seems to show only one equation. Both are there, but the dashed blue line sits on top of the dashed red line, so you can't see it. The purple shading indicates both red and blue shading in the same area.

===== =====

Of course you graph the boundary line the way you would any linear equation. In this form, it is not too difficult to see that both the x- and y-intercepts are 5. (When x=0, y=5; and when y=0, x=5 for the boundary line's equation x+y=5.) Draw the dotted line through these intercept points, add shading above, and you have your graph.

6 0
3 years ago
which is the slope of a line that is perpendicular to the line that passes through the points (29, 24) and (3, 4)?
Nataliya [291]

Answer:

26/20

Step-by-step explanation:

y2-y1 divided by x2-x1

4-24= -20

3-29= -26

-20/-26= m

perpendicular means to switch the numbers and change the sign

a perpendicular slope to -20/-26 is 26/20.

3 0
3 years ago
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