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nadezda [96]
3 years ago
14

Carrie works on a help desk and is assigned a ticket that was automatically generated by a server because of an error. The error

message states that the server has run out of storage space because logs were not set to delete at a certain age. Rather than going to the data center to physically access that server on the rack, what Windows tool might Carrie use to troubleshoot the server?
Computers and Technology
2 answers:
tino4ka555 [31]3 years ago
8 0

Answer:

The correct answer is: PowerShell.

Explanation:

PowerShell is a console interface with writing and commands instructions capabilities. This interface is designed for administrators' system users only so tasks in bulk can be automated in a more organized way. The interface is available for Windows and Linux OS.

mixas84 [53]3 years ago
5 0

The windows tool of weapon of choice that Carrie will use to troubleshoot the server is Powershell. All those GUI consoles built by Microsoft for Windows, by default, execute Powershell commands behind the scenes. Every possible thing that Carrie can do with the physical server can easily be accessible through Powershell's command line interface

Further Explanation

I would honestly say that there are a few available tools that Carrie can use, but the best tool is the inbuilt Windows Powershell. As Powershell continues to extend its purpose and usefulness, Microsoft, on the other hand, continues to use Powershell's capability to develop more cmdlets for products like Windows Servers.

Everything that can be done in a GUI environment can be done in Powershell. Carrie should be able to use Powershell to run things more efficiently from the command line without stepping a foot on the physical server. She will only need to access the server from her desk remotely, run a few commands, and that is it. Powershell command line is so powerful; it carries with it every troubleshooting pack that you can think about.

Learn More

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Explanation:

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Write a function called factor that determines for a pair of integers whether the second integer is a factor of the first. The f
Aleks04 [339]
<h2>Answer:</h2>

//import the Scanner class to allow for user's input

import java.util.Scanner;

//Declare the class and call it FactorClass

public class FactorClass {

   

   //Declare the function factor

   //It returns either true or false, therefore the return type is boolean

   //It receives two arguments - a and b

   public static boolean factor(int a, int b){

       

       //Check if a is divisible by b.

       //Return true if yes

       if(a % b == 0){

           return true;

       }

       

       //return false if a is not divisible by b

       return false;

   

   }  // End of method factor

   

   

   //The main method to test the function factor()

   public static void main(String[] args) {

       

       //Create an object of the Scanner class

       Scanner input = new Scanner(System.in);

       

       //Prompt the user to enter the pair of numbers

       System.out.println("Enter the pair of numbers (separated by a space)");

       

       //grab and store the first number in a variable

       int firstnum = input.nextInt();

       

       //grab and store the second number in another variable

       int secondnum = input.nextInt();

       

       

       //With the variables, call the factor() method

       //If it returns true, print the adequate message

       if(factor(firstnum, secondnum)){

           System.out.println(secondnum + " is a factor of " + firstnum);

       }

       

       //If it returns false, print the adequate message

       else{

           System.out.println(secondnum + " is NOT a factor of " + firstnum);

       }

   

 }            // End of main method

   

}    // End of class declaration

==============================================================

<h2>Sample Output 1:</h2>

>> Enter the pair of numbers  separated by a space

8 4

>> 4 is a factor of 8

==============================================================

<h2>Sample Output 2:</h2>

>> Enter the pair of numbers  separated by a space

9 4

>> 4 is NOT a factor of 9

==============================================================

<h2>Explanation:</h2>

The above code has been written in Java and it contains comments explaining every segment of the code. Kindly go through the comments for better understanding of the code.

For simplicity, the code is re-written as follows with little or no comments;

import java.util.Scanner;

//Declare the class and call it FactorClass

public class FactorClass {

   

   public static boolean factor(int a, int b) {

       if(a % b == 0){

           return true;

       }

       

       //return false if a is not divisible by b

       return false;

   

   }  // End of method factor

   

   

   //The main method to test the function factor()

   public static void main(String[] args) {

       

       //Create an object of the Scanner class

       Scanner input = new Scanner(System.in);

       

       //Prompt the user to enter the pair of numbers

       System.out.println("Enter the pair of numbers (separated by a space)");

       

       //grab and store the first number in a variable

       int firstnum = input.nextInt();

       

       //grab and store the second number in another variable

       int secondnum = input.nextInt();

       

       

       if(factor(firstnum, secondnum)){

           System.out.println(secondnum + " is a factor of " + firstnum);

       }

       

       else{

           System.out.println(secondnum + " is NOT a factor of " + firstnum);

       }

    }

   

}

3 0
3 years ago
What does a computer use long-term memory, or ROM, for?
AysviL [449]
The answer is B

Explanation: In contrast, a computer's hard disk or SDD is its long-term memory, where things are stored more or less permanently. ... Nearly all computers also have some way to store information for longer-term access, too.

5 0
3 years ago
Suppose a program takes 1000 machine instructions to run from start to end, and can do that in 10 microseconds when no page faul
Tema [17]

Answer:

(10^6 + 9.9)

Explanation:

Given:

Total number of machine instructions = 1000

Number of page fault in 100 instructions = 1

Number of page faults in 1000 instructions = 10

Time to serve one page fault = 100 milliseconds

Time to serve ten page faults = 100*10 milliseconds = 1000 milliseconds = 10^6 Microseconds

Number of instructions without any page fault = 1000 - 10 = 990

Time required to run 1000 instructions = 10 Microseconds

So, time required to run 990 instructions = (10*(990/1000)) Microseconds = 9.9 Microseconds

So, the total time required to run the program = (10^6 + 9.9) Microseconds

3 0
3 years ago
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