Answer:
6 address lines
Explanation:
The computation of the number of address lines needed is shown below:
Given that
Total memory = 64MB
= 
=
Also we know that in 1MB RAM the number of chips is 6
So, the number of address lines is 
i..e 26 address lines
And, the size of one chip is equivalent to 1 MB i.e. 
For a single 1MB chips of RAM, the number of address lines is
Therefore 6 address lines needed
Answer:
<u>VLANs</u>
Explanation:
Virtual LANs (VLANs) are a type of network connection or arrangement of network devices in the same broadcast domain. They are called Virtual LANs because they represent fractions or subgroups in the switch ports found in an Ethernet LAN.
Indeed, because of their topological arrangement, this reduces the security risk of unauthorized access to sensitive data or devices since the host can be placed on a different VLAN. Hence, in this scenario, using this network feature would allow visitors to plug into these ports to gain internet access, but they would not have access to any other devices on the private network.
Answer:
Redundant paths can be available without causing logical Layer 2 loops.
Explanation:
- Spanning Tree Protocol is used to allow redundancy in the Layer 2 switched networks without creating cycles/circles also called loops.
- These loops are called physical loops.
- When two parts of the switched network are connected via two or more Layer 2 switches this result in a loop.
- This affects the performance of the network as the result of broadcast packets flooding.
- STP puts one port of the switch to forward mode and the rest of the ports within the same part of the network to the blocking mode to avoid broadcast packet flooding. STP puts all the ports that are allowing redundant paths to block mode and the one port that is left after this is placed in forward mode.
- Spanning Tree Algorithm is used by STP to determine the optimal path of switch to the network.
- Bridge Protocol Data Units are used to share the information about the optimal path determined by the spanning tree algorithm with other switches.
- This information helps STP to eliminate the redundant paths.
- So this is how STP tracks all the links in the switched network and eliminates redundant loops by allowing only one active path to the destination while blocking all other paths.
we translate the following statement given in terms of logarithms. 211 base x can be expressed into log 211 / log x while 152 base 8 can be expressed int o log 152 over log 8. In this case,
log 211 / log x = log 152 / log 8log x = 0.962x = 10^0.962 = 9.1632
Answer:
The Anonymous Block will be:
1 DECLARE
2
3 lv_grade_row grade%rowtype;
4 lv_gr_avg grade.gr_t1%type;
5 lv_std_name varchar2(80);
6 cursor cursor_grade is select * from grade;
7
8 BEGIN
9
10 select avg(gr_t1) INTO lv_gr_avg from grade;
11 open cursor_grade;
12 fetch cursor_grade INTO lv_grade_row;
13
14 while cursor_grade%found loop
15
16 if
17 lv_grade_row.gr_t1>lv_gr_avg then lv_std_name :=
lv_grade_row.std_fname|| ' ' ||lv_grade_row.std_lname|| ' ' ||
lv_grade_row.gr_t1;
18 dbms_output.put_line(lv_std_name);
19
20 end if;
21 fetch cursor_grade into lv_grade_row;
22
Explanation:
