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Liono4ka [1.6K]
3 years ago
7

WhaT is the decimal for of 92/125

Mathematics
1 answer:
tatyana61 [14]3 years ago
7 0

Answer:

0.736

Step-by-step explanation:

You do 92/125. This / means divide. So you do 92 divide by 125=0.736.

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Can you solve some of these? Or all, whichever one you might know. Also explain please.
Rina8888 [55]
Here's number 5. If you need more explanation just let me know.

8 0
3 years ago
What is the value of x? There is isosceles triangle. The measure of angle which is between two congruent sides is (6x+10⁰). The
max2010maxim [7]
<h3><u>Answer</u><u>:</u><u>-</u></h3>

x=17

<h3><u>step-by</u><u>-</u><u>step</u><u> </u><u>Explanation</u><u>:</u><u>-</u></h3>

{\boxed{\quad\:\mapsto\rm Firstly\:Let's\:understand\:the\:concept:-}}

<h3 />

This is a isosceles triangle. As it is a triangle we can apply sum theory. we have to take the sum of given unknown polynomials as 180° .Then by solving it we can find the value of x.

<h3><u>Solution</u><u>:</u><u>-</u></h3>

Given angles

  • (6x+10°)
  • (x+17°)
  • (4x-34)°

According to sum theory

{\boxed{\sf The \:sum\:of\:angles=180°}}

  • Substitute the values

\qquad \quad{:}\longmapsto\tt (6x+10)+(x+17)+(4x-34)=180

  • Remove brackets

\qquad \quad{:}\longmapsto\tt 6x+10+x+17+4x-34=180

  • Together like polynomials and constants

\qquad \quad{:}\longmapsto\tt 6x+x+4x+10+17-34=180

\qquad \quad{:}\longmapsto\tt 11x-7=180

  • Interchange sides

\qquad \quad{:}\longmapsto\tt 11x=180+7

\qquad \quad{:}\longmapsto\tt 11x=187

\qquad \quad{:}\longmapsto\tt x=\cancel{\dfrac{187}{11}}

  • Simplify

\qquad \quad{:}\longmapsto\tt x=17

\therefore\sf The \:value\:of\:x\;is\:17.

8 0
3 years ago
72% of what number is 27?
Tems11 [23]
72 is 266.666666667% of 27
3 0
3 years ago
Read 2 more answers
The product of two and x plus the quotient of w and five
Nataly [62]

Answer:

2x+w/5

Step-by-step explanation:

(2*x)+(w/5)

2x +w/5

8 0
3 years ago
How does it factor out as that?
eimsori [14]
To factor out you have to think what multiples to AC and adds to B.

Ax^2+Bx+C

So... for this problem AxC=1x-24 or -24

B is -2.

So what two numbers multiply to -24: -3x8, -8x3, -4x6, -6x4, -2x12, -12x2.

Out of these, which adds to -2: -6+4=-2.

So the factors are (d-6)(d+4)

OR the longer way, which you really only use if A is not equal to 1.

Use the terms above and then rewrite the equation with two middle terms: d^2+4d-6d-24

Group the terms by using addition: (d^2+4d)+(6d-24)

Find what they have in common and factor it out. For the first, it's d. They both have d. So: d(d+4)
To check this, distribute the d. It should equal the first set lf parenthesis.

For the second, they have a number in common. 6 is a multiple of 24 so you can take that out: -6(d+4)

If the terms inside the parenthesis are the same, that's good. It means we can pair the insides and the outsides together to form the factors.

The two terms outside the parenthesis: d, -6 group together and become (d-6)

The inside terms stay the same: (d+4)

(d-6)(d+4)

Again, this is the longer way and no necessary for a problem like this. But if it was 2d^2, then this would be perfecf.




6 0
3 years ago
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