Question

I need help please ASAP thank you

Answer 1

Answer:

The products of AB and BA is given by

AB=$\left[\begin{array}{cc}21&-6\\ 9&3\end{array}\right]$

BA=$\left[\begin{array}{cc}9&-1\\-18&15\end{array}\right]$

Step-by-step explanation:

Given the matrices A=$\left[\begin{array}{cc}6&-5\\-3&-4\end{array}\right]$ and

B=$\left[\begin{array}{cc}1&-1\\-3&0\end{array}\right]$

To find the product AB and BA

AB=$\left[\begin{array}{cc}6&-5\\-3&-4\end{array}\right] \left[\begin{array}{cc}1 & -1\\-3 &0\end{array}\right]$

$=\left[\begin{array}{cc}6+15& -6+0\\-3+12&3-0\end{array}\right]$

Therefore the product of AB is

AB=$\left[\begin{array}{cc}21&-6\\ 9&3\end{array}\right]$

BA=$\left[\begin{array}{cc}1&-1\\-3&0\end{array}\right]$ $\left[\begin{array}{cc}6&-5\\-3&-4\end{array}\right]$

$=\left[\begin{array}{cc}6+3& -5+4\\-18+0&15+0\end{array}\right]$

Therefore the product of BA is

BA=$\left[\begin{array}{cc}9&-1\\-18&15\end{array}\right]$

The products of AB and BA is given by

AB=$\left[\begin{array}{cc}21&-6\\ 9&3\end{array}\right]$

BA=$\left[\begin{array}{cc}9&-1\\-18&15\end{array}\right]$