Ask question

Ask question

All categories

2 years ago

7

Can you please help meee

1 answer:

Lubov Fominskaja [6]2 years ago

5 0

Answer: y = 4x + 5/4

Step-by-step explanation: Plug in the slope and y-intercept into the equation y = mx + b, where m is the slope and b is the y-intercept, and such that m, b ≠ 0.

You might be interested in

Convert 9 1/3 to a decimal.

nataly862011 [7]

B) 9.3
9 is already a whole number. 1 divided by 3 is .33 repeated, which rounds to .3.
9.0 + 0.3 = 9.3

3 0

4 years ago

Read 2 more answers

I need help for grades!!!

irina1246 [14]

Yes, the relation shown is a function because every element in the domain has only one distinct image in the co-domain.

5 0

3 years ago

The total cost of five pens and eight mechanical pencils is 12.65. The cost of each mechanical pencil is 0.75 cents. Which repre

Tanya [424]

Answer:

the cost of each pen is 1.33

Step-by-step explanation:

if you multiply 0.75 by 8 you get 6 after that you subtract 6 from 12.65 which means you have 6.65 which you divide by 5 which equals 1.33

7 0

3 years ago

5. What value of x is not included in the domain of the function y =<br> X+ 12<br> ? Why?

Minchanka [31]

X=-12,0
Y=-0,12 hope this helps:/

8 0

3 years ago

Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations

marusya05 [52]

Answer:

$Sin \angle A =0.80$

$Cos \angle A=0.60$

$Sin \angle B =0.60$

$Cos \angle B=0.80$

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle A =\frac{BC}{BA}$

Substitute values for BC and BA

$Sin \angle A =\frac{8cm}{10cm}$

$Sin \angle A =\frac{8}{10}$

$Sin \angle A =0.80$

$Cos \angle A=\frac{AC}{BA}$

Substitute values for AC and BA

$Cos \angle A=\frac{6cm}{10cm}$

$Cos \angle A=\frac{6}{10}$

$Cos \angle A=0.60$

Solving (b): Sine and Cosine B

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

So:

$Sin(53^{\circ}) =0.7986$

$Sin(53^{\circ}) =0.80$ -- approximated

$Cos(53^{\circ}) = 0.6018$

$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

$Cos(37^{\circ}) = 0.7986$

$Cos(37^{\circ}) = 0.80$ --- approximated

8 0

3 years ago

Read 2 more answers