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arlik [135]
3 years ago
7

A square dinner napkin 8 inches on each side is folded along it's diagonal.find the area of the folded napkin

Mathematics
1 answer:
trasher [3.6K]3 years ago
7 0
The area of the folded napkin is 32 sq in. This is because if you find the area of the napkin normally, you will get 64, because 8*8 is 64. If you divide that by 2, you will get 32.
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1/(x-2)+1/(x+3)=1/5 solve the problem for me​
Gennadij [26K]

════════ ∘◦❁◦∘ ════════

<h3>Final value : x² -9x - 11</h3>

════════════════════

<h3>Step by step </h3>

\frac{1}{(x - 2)}  +  \frac{1}{(x + 3)}  =   \frac{1}{5}

\frac{(x + 3) + (x - 2)}{(x - 2)(x + 3)}  =  \frac{1}{5}

\frac{2x + 1}{ {x}^{2} + 3x - 2x - 6 }  =  \frac{1}{5}

\frac{2x + 1}{ {x}^{2}  + x - 6}  =  \frac{1}{5}

2x + 1 = ⅕ × (x² + x - 6)

2x + 1 = ⅕x² + ⅕x - 6/5

1/5x² +1/5x - 2x - 6/5 - 1 = 0

1/5x² -9/5x - 11/5 = 0

x² - 9x - 11 = 0. #times by 5

════════════════════

#Give me brainliest pls im tired typing all of this

8 0
3 years ago
Which of the following statements must be true based on the diagram below?(Diagram is not to scale.)FDEO EF is a segment bisecto
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From the diagram given;

ABCD is a quadrilateral;

Line |EF| bisects the line |AD| and line |CD|,

Thus, from the given options;

LINE |EF| is a segment bisector is the only correct option.

6 0
1 year ago
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