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arlik [135]
4 years ago
7

A square dinner napkin 8 inches on each side is folded along it's diagonal.find the area of the folded napkin

Mathematics
1 answer:
trasher [3.6K]4 years ago
7 0
The area of the folded napkin is 32 sq in. This is because if you find the area of the napkin normally, you will get 64, because 8*8 is 64. If you divide that by 2, you will get 32.
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On a test each student is given a grade of a b c d or f witch measure tells the grade given most often
topjm [15]

Answer:

lets see i think it would be a graph

Step-by-step explanation:

4 0
3 years ago
What is 30% as a decimal in its simplest form
KATRIN_1 [288]
.3 is what 30% would be as a decimal, seeing as 30/100=.3
7 0
4 years ago
A class of 90 students voted for class president. 60% of the students voted for John, and 40% voted for Mike. How many votes did
nikklg [1K]

Answer:

54 votes

Step-by-step explanation:

John was the winner

so: 60% of 90 = 54

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4 0
2 years ago
Use the quadratic function f(x) = 2x^2 + 4x - 15. Find any x intercepts.
8_murik_8 [283]

So for this function we will be using the quadratic formula, which is x=\frac{-b+\sqrt{b^2-4ac}}{2a},\frac{-b-\sqrt{b^2-4ac}}{2a} , to solve. a = x^2 coefficient, b = x coefficient, and c = constant. Using our equation, we can solve for the zeros (x-intercepts) as such:

x=\frac{-4+\sqrt{4^2-4*2*(-15)}}{2*2},\frac{-4-\sqrt{4^2-4*2*(-15)}}{2*2}\\ \\ x=\frac{-4+\sqrt{16-(-120)}}{4},\frac{-4-\sqrt{16-(-120)}}{4}\\ \\ x=\frac{-4+\sqrt{136}}{4},\frac{-4-\sqrt{136}}{4}\\ \\ x=1.92,-3.92

In short, your x-intercepts (rounded to the hundredths) are (1.92,0) and (-3.92,0).

6 0
4 years ago
What is a, b, and c in this quadratic equation?
coldgirl [10]

Answer:

<h2>a = 8, b = −19, c = −89</h2>

Step-by-step explanation:

The quadratic equation:

ax^2+bx+c=0

We have:

8x^2-19x=89         <em>subtract 89 from both sides</em>

8x^2-19x-89=0

8x^2+(-19)x+(-89)=0

Therefore:

a=8\\b=-19\\c=-89

5 0
4 years ago
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