On a test each student is given a grade of a b c d or f witch measure tells the grade given most often

Mathematics

1 answer:

topjm [15]2 years ago

4 0

Answer:

lets see i think it would be a graph

Step-by-step explanation:

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A grocery store sells avocados for $1.25 each. The graph shows the cost for different numbers of avocados.

Aleksandr [31]

I don’t know if this is right or not so, sorry if it’s wrong ;-;

1,2,3,4,5 = independent

c=1.25a = neither

$1.25, $2.50, $3.75, $5.00, $6.25 = dependent

Number of avocados = independent

Cost of avocados = dependent

If this is right then I’ll put the explanation in the comments, again sorry if it isn’t.

5 0

2 years ago

The percentage of body fat of a random sample of 36 men aged 20 to 29 found a sample mean of 14.42. Find a 95% confidence interv

Rina8888 [55]

Answer:

$14.42-1.96\frac{6.95}{\sqrt{36}}=12.150$

$14.42+ 1.96\frac{6.95}{\sqrt{36}}=16.690$

So on this case the 95% confidence interval would be given by (12.150;16.690)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=14.42$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=6.95$ represent the population standard deviation

n=36 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$