Answer:
Csc(pi)
Cot(pi)
Csc(0)
Sec(90)
Step-by-step explanation:
Answer:
The student is expected to spend <em>15.4 hours </em>doing homework
Step-by-step explanation:
The scattered plot shows there is a close correlation between the variables. A line of best fit will go through the 'center' of the points. Since we are not required to find an exact line, we'll draw it in red color as shown below
To know the equation of that line, we must take two clear points of it from the graph. We'll pick (28,4) and (4,25)
The equation of a line, given two points (a,b) and (c,d) is
Using the selected points
Simplifying and computing results, the equation is
Using that equation, we can predict how many hours the students will spend doing homework if they spend 15 hours watching TV
=15.4 hours
So the student is expected to spend 15.4 hours doing homework
Answer: B
Step-by-step explanation: You just multiplying 25 with 10 and w which can be simplified as 24(w+10) and adding with the 13.5 x 10 and 13.5 x w, which can be simplified as 13.5(10+w)
100$×0.05= 5 $ is her annual interest
qusetion number 1 . 5$× 6 years = 30 $
for question number 2 . 100$+30$=130$
<em>A) 22cm</em>
<em>(</em><em> </em><em>divide the length value by 100</em><em>)</em>
<em>2</em><em>2</em><em>/</em><em>1</em><em>0</em><em>0</em><em> </em><em>which</em><em> </em><em>gives</em><em> </em><em>you</em><em>:</em>
<em><u>=</u></em><em><u>0.22m</u></em>
<em>B</em><em>)</em><em> </em><em>180km</em>
<em>(</em><em> </em><em>multiply the length value by </em><em>1000</em><em>)</em>
<em>1</em><em>8</em><em>0</em><em>×</em><em>+</em><em>1</em><em>0</em><em>0</em><em> </em><em>which</em><em> </em><em>gives</em><em> </em><em>you</em><em>:</em>
<em><u>=</u></em><em><u>180000m</u></em>
<em>C</em><em>)</em><em> </em><em>300mm</em>
<em>(</em><em> </em><em>divide the length value by 1000</em><em>)</em>
<em>3</em><em>0</em><em>0</em><em>/</em><em>1</em><em>0</em><em>0</em><em>0</em><em> </em><em>which</em><em> </em><em>gives</em><em> </em><em>you</em><em>:</em>
<em><u>=</u></em><em><u>0.3m</u></em>
<em> </em>
