Two cargo ships spot a signal fire on a small island. The captains know they are 140 feet

dem82 [27]

So we see that the ratio between the two octagons is 7:1, since 28/4=7 so what we do next is multiply the values of the smaller octagon by 7. But that’s the long way. There’s actually a shortcut by multiplying the perimeter of the smaller octagon, 34, by 7. This in turn equals 238.

6 0

3 years ago

Read 2 more answers

What is the scientfic notation of 0.05

vredina [299]

Answer:

5×10⁻²

Step-by-step explanation:

Move the decimal so there is one non-zero digit to the left of the decimal point.
The number of decimal places you move will be the exponent on the 10. a. If the decimal is being moved to the right, the exponent will be negative.

b. If the decimal is being moved to the left, the exponent will be positive.

Therefore. The answer is 5×10⁻²

8 0

3 years ago

What is the x intercept?

Harlamova29_29 [7]

The line that is horizontal on a graph
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7 0

3 years ago

Let X be a set of size 20 and A CX be of size 10. (a) How many sets B are there that satisfy A Ç B Ç X? (b) How many sets B are

Svetlanka [38]

Answer:

(a) Number of sets B given that

A⊆B⊆C: 2¹⁰. (That is: A is a subset of B, B is a subset of C. B might be equal to C)
A⊂B⊂C: 2¹⁰ - 2. (That is: A is a proper subset of B, B is a proper subset of C. B≠C)

(b) Number of sets B given that set A and set B are disjoint, and that set B is a subset of set X: 2²⁰ - 2¹⁰.

Step-by-step explanation:

Let $x_1, x_2, \cdots, x_{20}$ denote the 20 elements of set X.

Let $x_1, x_2, \cdots, x_{10}$ denote elements of set X that are also part of set A.

For set A to be a subset of set B, each element in set A must also be present in set B. In other words, set B should also contain $x_1, x_2, \cdots, x_{10}$ .

For set B to be a subset of set C, all elements of set B also need to be in set C. In other words, all the elements of set B should come from $x_1, x_2, \cdots, x_{20}$ .

$\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}& \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{Maybe} & \cdots & \text{Maybe}\end{array}$ .

For each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus $2^{10} = 1024$ possibilities for set B.

In case the question connected set A and B, and set B and C using the symbol ⊂ (proper subset of) instead of ⊆, A ≠ B and B ≠ C. Two possibilities will need to be eliminated: B contains all ten "maybe" elements or B contains none of the ten "maybe" elements. That leaves $2^{10} -2 = 1024 - 2 = 1022$ possibilities.

Set A and set B are disjoint if none of the elements in set A are also in set B, and none of the elements in set B are in set A.

Start by considering the case when set A and set B are indeed disjoint.

$\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}& \text{No}&\text{No}&\cdots &\text{No}& \text{Maybe} & \cdots & \text{Maybe}\end{array}$ .

Set B might be an empty set. Once again, for each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus $2^{10} = 1024$ possibilities for a set B that is disjoint with set A.

There are 20 elements in X so that's $2^{20} = 1048576$ possibilities for B ⊆ X if there's no restriction on B. However, since B cannot be disjoint with set A, there's only $2^{20} - 2^{10}$ possibilities left.

5 0

2 years ago

Magnitude statistics allow one to draw general conclusions about a population from information collected in a population sample.

kow [346]

inferential statistics allows for someone to draw conclusions about a population from the information collected in a population sample.

the qestion is incomplete .please read below to find the missing content

Which of the following allows for someone to draw conclusions about a population from the information collected in a population sample?

a. magnitude statistics

b. central tendency

c. inferential statistics

d. effect size

The population is the number of people living together in a place. The population of a city is the number of people living in that city. These people are called residents or residents. The population includes all individuals living in that particular area.

Population refers to the total number of organisms living in a particular area. Population helps us estimate the number of beings and know how to act accordingly. For example, knowing the exact population of a city allows us to estimate the number of resources required. Similarly, animals can do the same.

Learn more about the population here

brainly.com/question/25896797

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5 0

1 year ago